Question

A monochromatic light of wavelength 506 nm from a distant source is incident on a single slit 0.075 mm wide. Diffraction pattern is observed at a distance of 2.0 m. Calculate the distance of first minimum from the center.

Answer 1

Answer:

first minimum distance from the center = 0.417 m m

Explanation:

given,

wavelength (λ) = 506 nm

d = 0.075 mm  = 0.000075 m

tanθ = x /2

d sinθ = m λ

m=1 ( 1 st minimum  )  

0.000075 × sin θ = 506 × 10⁻⁹

sin θ =$\dfrac{506 × 10⁻⁹}{0.000075}$

sin θ = 0.00675

θ = sin⁻¹(0.00675)

θ = 0.00675

x =  0.000417 m

hence, the first minimum distance from the center = 0.417 m m