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atroni [7]
3 years ago
14

The force required to stretch a Hooke’s-law

Physics
1 answer:
Setler [38]3 years ago
5 0

I think this is correct, but I am not entirely certain.

Find the force constant of the spring:

F = - KX

(0 - 62.4) = -K(0.172m)

-362.791 = -K

362.791 N/m = K


Find the work done in stretching the spring:

W = (1/2)KX

W = (1/2)(362.791)(0.172m)

W = 31.2 J


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