Answer:
E = 12640.78 N/C
Explanation:
In order to calculate the electric field you can use the Gaussian theorem.
Thus, you have:

ФE: electric flux trough the Gaussian surface
Q: net charge inside the Gaussian surface
εo: dielectric permittivity of vacuum = 8.85*10^-12 C^2/Nm^2
If you take the Gaussian surface as a spherical surface, with radius r, the electric field is parallel to the surface anywhere. Then, you have:

r can be taken as the distance in which you want to calculate the electric field, that is, 0.795m
Next, you replace the values of the parameters in the last expression, by taking into account that the net charge inside the Gaussian surface is:

Finally, you obtain for E:

hence, the electric field at 0.795m from the center of the spherical shell is 12640.78 N/C
Answer:
<h2>volume= 0.85m^3</h2>
Explanation:
<em>The density of a substance is defined as the mass per unit volume of the substance, the unit is in kg/m^3 and it is represented by the greek letter rho</em>
Step one:
given data
we are told that the density of Co2= 1.98 kg/m3
and the mass of Co2 is= 1.70 kg
we know the relation between mass, volume and density is

make volume subject of formula we have

substitute we have

Answer:
Explanatioyour answers look right, but if there has , has to be another answer its a , but your answers are right
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"The accident only released harmless gamma rays."
Hope I helped!