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lyudmila [28]
3 years ago
14

What is penetration? How is it related to shielding? Use the penetration effect to explain the difference in relative orbital en

ergies of a 3p and a 3d electron in the same atom.
Chemistry
1 answer:
Whitepunk [10]3 years ago
5 0

Answer: penetration is the ability of an electron in a given orbital to approach the nucleus closely. Shielding refers to the fact that core electrons reduce the degree of nuclear attraction felt by the orbital electrons. Shielding is the opposite of penetration. The most penetrating orbital is the least screening orbital. The order of increasing shielding effect/decreasing penetration is s<p<d<f.

Explanation:

The order of penetrating power is 1s>2s>2p>3s>3p>4s>3d>4p>5s>4d>5p>6s>4f....

Since the 3p orbital is more penetrating than the 3d orbital, it will lie nearer to the nucleus and thus possess lower energy.

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Argon occupies a volume of 28.3 L at a pressure of 0.36 atm. Find the volume of argon when the pressure is increased to 0.85 atm
FromTheMoon [43]

Answer:

12

Explanation:

Boyles law

P1 (.36)

V1(28.3)

P2(.85)

V2(?)

P1*V1=P2*V2

plug it in, and you get 12

3 0
3 years ago
(A tablet containing calcium carbonate and fillers with a mass of 1.631 g was dissolved in HCl. After the fillers were filtered
FrozenT [24]

Answer:

1) 0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

2) The mass % calcium carbonate in the tablet is 50.58%.

3) The mass % of calcium in calcium carbonate  is 40.00 %.

4) Mass of calcium in a tablet is 0.33 g.

Explanation:

Mass of tablet = 1.631 g

Mass of the watch glass = 46.719 g

Mass of the watch glass + mass of calcium carbonate = 47.544 g.

Mass of calcium carbonate = 47.544 g - 46.719 g = 0.825 g

0.825 grams is the mass of pure calcium carbonate product collected at the end of the experiment.

Mass of calcium carbonate = 0.825 g

Percentage of calcium in tablet:

\%=\frac{\text{Mass of calcium carbonate }}{\text{Mass of tablet}}\times 100

\%=\frac{0.825 g}{1.631 g}\times 100=50.58\%

The mass % calcium carbonate in the tablet is 50.58%.

Percentage of calcium in calcium carbonate :

Molar mass of calcium carbonate = 100 g/mol

Atomic mass of calcium = 40 g/mol

Percentage of calcium in calcium carbonate :

\%=\frac{\text{atomic mass of calcium}}{\text{Molar mass of}CaCO_3}\times 100

\%=\frac{40 g/mol}{100 g/mol}\times 100=40.00\%

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium carbonate = 0.825 g

The mass % of calcium in calcium carbonate  is 40.00 %.

Mass of calcium in a tablet : x

40.00\%=\frac{\text{Mass of calcium in a tablet}}{0.825 g}\times 100

x=40.00\times \frac{0.825 g}{100}=0.33 g

Mass of calcium in a tablet is 0.33 g.

3 0
3 years ago
I NEED HELP AND WILL RATE BRAINLIEST!!!!
11Alexandr11 [23.1K]

Answer:

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4 0
3 years ago
How many nonmetals are on the periodic table?
jekas [21]
There are 17 nonmetals
7 0
3 years ago
Given that the density of water is 0.975 g/ml and that 171 g of sucrose (molar mass: 342.30 g/mol) is dissolved in 512.85 ml of
VMariaS [17]
Molality is defined as the number of moles of solute in 1 kg of solvent .
the mass of water - 512.85 ml x 0.975 g/ml = 500 g
number of moles of solute in 500 g of water - 171 g / 342.30 g/mol = 0.500 mol
the number of sucrose moles in 500 g of water - 0.500 mol
therefore number of sucrose moles in 1 kg water - 0.500 mol / 0.500 kg = 1.00 
molality of solution - 1.00 M
6 0
3 years ago
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