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Gwar [14]
4 years ago
8

40.3 degrees Fahrenheit. Each hour the temperature decreases by 2.09 What is the

Chemistry
1 answer:
Murrr4er [49]4 years ago
6 0
ANSWER

36.12 degrees fahrenheit
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Which form of bonding holds cesium chloride (CsCl) together?
Talja [164]
The correct answer is D. Cesium chloride is held together by ionic bonding. This substance is a salt like sodium chloride. It is also soluble in water. When it dissociates, it forms into cesium ions and chloride ions. 
3 0
4 years ago
HELP DUE IN 5MIN WILL MARK BRAILIEST
Stells [14]

Explanation:

The problem deals with a phase transition from solid to liquid. To the left we have ice and to the right we have liquid water.

For such change to take place, the process of melting must occur. During melting, a solid changes state from solid to liquid by taking energy from the environment.

  • In solid state, the molecules of the water are in a fixed state about their fixed lattice.
  • As the solid ice gains energy from the environment, it begins to melt.
  • Energy increase causes the molecules of the water to start flowing to form a liquid.
6 0
3 years ago
How could you measure the average kinetic energy of a group of particles
dexar [7]

Answer:

Temperature measures the average kinetic energy of the particles in a substance. Thermal energy measures the total kinetic energy of the particles in a substance. The greater the motion of particles, the higher a substance's temperature and thermal energy.

Explanation:

8 0
3 years ago
Read 2 more answers
Copper(II) sulfate forms a bright blue hydrate with the formula CuSO 4 ⋅ n H 2 O ( s ) . If this hydrate is heated to a high eno
Arada [10]

Answer:

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

Explanation:

CuSO_4.nH_2O\rightarrow CuSO_4+nH_2O

Mass of hydrate of copper sulfate = 14.220 g

Moles of hydrate of copper sulfate =\frac{14.220 g}{(159.5+n\times 18) g/mol}

Mass of copper sulfate after heating = 8.9935 g

Moles of copper sulfate = \frac{8.9935 g}{159.5 g/mol}

\frac{14.220 g}{(159.5+n\times 18) g/mol}=\frac{8.9935 g}{159.5 g/mol}

Solving for n, we get:

n = 5

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

5 0
3 years ago
What is the density of heavy water?
vlada-n [284]
<span>1.11 g/cm³

Hope this helps! </span>
6 0
3 years ago
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