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kumpel [21]
3 years ago
10

The number of protons in the nucleus is always equal to the number of neutrons. True or False?

Chemistry
2 answers:
vekshin13 years ago
7 0
False. The number of neutrons can be more or less than the number of protons.
goldfiish [28.3K]3 years ago
4 0
The answer is false , the printing in the nucleus equal to the atomic number
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Which of the following is true about cells?
Allushta [10]

Answer:

D

Explanation:

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8. Why would it be a bad idea to make coins made of sodium metal?
Elina [12.6K]

Answer:

Sodium reacts with the oxygen in air. It reacts vigorously with oxygen and the moisture that is already present in the air and thus catches fire.

5 0
3 years ago
In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
Correction?
rjkz [21]
Your answer is correct.

MgO(s) + H2O(l) ----> Mg(OH)2(aq)

:-) ;-)
5 0
3 years ago
Read 2 more answers
A 155 g sample of an unknown substance was heated from 25°c to 40°c. in the process, the substance absorbed 569 calories of ener
Tasya [4]
Energy= 2381 joules
heat= Mass(kg) *change in temperature(K) * Cp
2381=0.155*(15)*Cp
Cp=1024 J/kg K
5 0
4 years ago
Read 2 more answers
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