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ddd [48]
3 years ago
12

Fran swims at a speed of 2.62.6 ​km/h in still water. The Lazy River flows at a speed of 0.30.3 ​km/h. How long will it take Fra

n to swim 88 km​ upstream? 88 km​ downstream?
Physics
1 answer:
Mars2501 [29]3 years ago
8 0

Answer:

Fran's upstream time =  37.93 hrs

Fran's downstream time =  30.13 hrs

Explanation:

given data

speed in still water = 2.62 km/h

River flows = 0.3 km/h

Fran to swim upstream =  88 km​

solution

we will apply here distance formula that is

distance  = speed  × time   ...................1

put here value

so here

Fran's upstream speed = 2.62 km/h - 0.3 km/h  = 2.32 km/h

Fran's downstream speed = 2.62 km/h + 0.3 km/h = 2.92 km/h  

so

Fran's upstream time = \frac{88}{2.32}  = 37.93 hrs

Fran's downstream time = \frac{88}{2.92} = 30.13 hrs

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Answer:

230.4 N

Explanation:

From the question given above, the following data were obtained:

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The force exerted can be obtained as follow:

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5 0
3 years ago
Need help!!!<br> Physics due tomorrow help, help ,help
Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

F_{net}=F_{1}-F_{2}=26-8=14N

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

F_{x}=Fsin ( θ )= 67sin(73)=64N

then, as Q(1),

F_{net}=F_{1}-F_{2}=64-33=31 N

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

F_{Tension}=420 N

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

F_{x}=Fsin ( θ )= 600sin(45)=424.264N

F_{y} = F sin ( θ )= 600cos45)=424.264N

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N in east

F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N in south

The total net force for perpendicular forces is calculated from the relation:  

F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force  equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, F_{right}=F_{left}=55N

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4 years ago
A ball is launched up a semicircular chute in such a way that at the top of the chute, just before it goes into free fall, the b
Mariulka [41]

We have centripetal acceleration = v^2/r = 2g

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t = \sqrt{\frac{4r}{g} }

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A mechanic has a wrench where the hand grip is 0.40 m from the axis of the bolt. To apply a torque of 170 N m with this wrench w
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Answer:

4.3 * 10 N

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