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Mariulka [41]
2 years ago
13

A right triangle has a leg of 6 and a hypotenuse of 19. What is the other leg

Mathematics
1 answer:
nydimaria [60]2 years ago
5 0

Answer:

5\sqrt{13} or 18.03

Step-by-step explanation:

Let's call the unknown leg x

Using the Pythagoras rule

19^2 = 6^2 + x^2

361 = 36 + x^2

subtract 36 from both sides

361 - 36 = x^2

325 = x^2

Take the square root of both sides

\sqrt{325} = \sqrt{x^2}

\sqrt{25*13}\\ = x

x = 5\sqrt{13}  = 18.03

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Answer:

\frac{x^2}{25} +\frac{y^2}{16} =1

Step-by-step explanation:

For ellipses, the length of the major axis is represents as:

Major axis = 2a

where a is called the semi-major axis.

In this case since the major axis is equal to 10 units:

10=2a

solving for the semi-major axis a :

a=10/2\\a=5

and also the minor axis of an ellipse is represented as:

Minor axis = 2b

where b  is called the semi-minor axis.

Since the minor axis has a length of 8 units:

8=2b

solving for b:

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Now we can use the equation for an ellipse centered at the origin (0,0):

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1

and substituting the values for a and b:

\frac{x^2}{5^2} +\frac{y^2}{4^2} =1

and finall we simplify the expression to get the equation of the ellipse:

\frac{x^2}{25} +\frac{y^2}{16} =1

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2 years ago
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