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Maslowich
3 years ago
5

Quadrilateral OPQR is inscribed in circle N, as shown below. What is the measure of ∠ROP?

Mathematics
2 answers:
Murrr4er [49]3 years ago
8 0
The answer is 41, because I just took the quiz and that was the correct answer :)
Arte-miy333 [17]3 years ago
8 0

Answer:  The correct option is (A) 41°.

Step-by-step explanation:  Given that quadrilateral OPQR is inscribed in circle N as shown in the figure.

Also, ∠ROP = (x+17)°  and  ∠RQP = (6x-5)°.

We are to find the measure of ∠ROP.

Since quadrilateral OPQR is inscribed in a circle, so it is a cyclic quadrilateral.

We know that the sum of the measures of opposite angles of a cyclic quadrilateral is 180°.

So, in cyclic quadrilateral OPQR, we have

m\angle ROP+m\angle RQP=180^\circ\\\\\Rightarrow (x+17)^\circ+(6x-5)^\circ=180^\circ\\\\\Rightarrow (7x+12)^\circ=180^circ\\\\\Rightarrow 7x^\circ=168^\circ\\\\\Rightarrow x^\circ=\left(\dfrac{168}{7}\right)^\circ\\\\\Rightarrow x^\circ=24^\circ.

Therefore, we get

m\angle ROP=(x+17)^\circ=(24+17)^\circ=41^\circ.

Thus, the measure of angle ROP is 41°.

Option (A) is CORRECT.

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Show why x−3 is a factor of m(x)=x3−x2−5x−3. Justify your answer. You can show this using remainder theorem, long division, synt
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The factors of a polynomial function are the zeros of the function

It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3

<h3>How to show why the x - 3 is a factor</h3>

The function is given as:

m(x) = x^3 - x^2 - 5x - 3

The factor is given as:

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