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2 years ago

What are the similarities between a chemical change and a physical change?

Chemistry

2 answers:

Reil [10]2 years ago

7 0

Answer:

Physical and chemical changes are similar because they are both caused by the interaction of two or more particles.

Explanation:

Physical and chemical changes are similar because they are both caused by the interaction of two or more particles. Physical changes occur through vibrations, impacts, and other forms of movement. Chemical changes are caused by the interaction of two or more atoms or molecules.

alexgriva [62]2 years ago

3 0

Physical changes occur through vibrations, impacts, and other forms of movement. Chemical changes are caused by the interaction of two or more atoms or molecules.

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What is the formula (with cation and anion charges) for copper (II) hydroxide?

Thepotemich [5.8K]

Answer:

Cu²⁺(OH)⁻₂

Explanation:

Step 1: Find the symbols for the substances

For copper, see your periodic table. Copper is "Cu".

For hydroxide, see your polyatomic ions chart. Hydroxide is "OH".

Step 2: Find the charges for each element.

Copper (II)'s charge is 2, which is the roman numerals in the brackets.

Hydroxide's charge is -1.

Charges are written as superscripts. You do not need to write "1".

In formulas, write the positively charged atom first.

Cu²⁺(OH)⁻ Put brackets around hydroxide because it has 2 elements.

Step 3: Write the number of atoms.

The number of atoms that an element has is the same as its partner's charge.

The charge of copper is 2, so hydroxide has 2 atoms.

The charge of hydroxide is 1, so copper has 1 atom.

Cu²⁺₁(OH)⁻₂

You do not need to write the "1" for atoms.

Cu²⁺(OH)⁻₂

8 0

2 years ago

Molybdenum can form a wide series of halide compounds, including four different fluoride compounds. The percent by mass of molyb

azamat

The formula and names of the compounds are:

1. Formula of compound => MoF₃

Name of compound => Molybdenum trifluoride

2. Formula of compound => MoF₄

Name of compound => Molybdenum tetrafluoride

3. Formula of compound => MoF₅

Name of compound => Molybdenum pentafluoride

4. Formula of compound => MoF₆

Name of compound => Molybdenum hexafluoride

1. Determination of the name and formula of the molybdenum fluoride having 63.0% of molybdenum.

Molybdenum (Mo) = 63.0%

Fluorine (F) = 100 – 63 = 37%

<h3>Formula =? </h3>

Mo = 63.0%

F = 37%

Divide by their molar mass

Mo = 63.0 / 96 = 0.656

F = 37 / 19 = 1.947

Divide by the smallest

Mo = 0.656 / 0.656 = 1

F = 1.947 / 0.656 = 3

Therefore,

Formula of compound => MoF₃

Name of compound => Molybdenum trifluoride

2. Determination of the name and formula of the molybdenum fluoride having 56.0% of molybdenum.

Molybdenum (Mo) = 56.0%,

Fluorine (F) = 100 – 56 = 44%

<h3>Formula =? </h3>

Mo = 56%

F = 44%

Divide by their molar mass

Mo = 56 / 96 = 0.583

F = 44 / 19 = 2.316

Divide by the smallest

Mo = 0.583 / 0.583 = 1

F = 2.316 / 0.583 = 4

Therefore,

Formula of compound => MoF₄

Name of compound => Molybdenum tetrafluoride

3. Determination of the name and formula of the molybdenum fluoride having 50.0% of molybdenum.

Molybdenum (Mo) = 50.0%,

Fluorine (F) = 100 – 50 = 50%

<h3>Formula =? </h3>

Mo = 50%

F = 50%

Divide by their molar mass

Mo = 50 / 96 = 0.520

F = 50 / 19 = 2.632

Divide by the smallest

Mo = 0.520 / 0.520 = 1

F = 2.632 / 0.520 = 5

Therefore,

Formula of compound => MoF₅

Name of compound => Molybdenum pentafluoride

4. Determination of the name and formula of the molybdenum fluoride having 46.0% of molybdenum.

Molybdenum (Mo) = 46.0%,

Fluorine (F) = 100 – 46 = 54%

<h3>Formula =? </h3>

Mo = 46%

F = 54%

Divide by their molar mass

Mo = 46 / 96 = 0.479

F = 54 / 19 = 2.842

Divide by the smallest

Mo = 0.479 / 0.479 = 1

F = 2.842 / 0.479 = 6

Therefore,

Formula of compound => MoF₆

Name of compound => Molybdenum hexafluoride

Learn more: brainly.com/question/11185156

7 0

2 years ago

1. As Z stays constant and the number of electrons increases, the electron-electron repulsions _____, and the anion becomes larg

Ray Of Light [21]

Answer:

1) increases

2) smaller

Explanation:

Generally, as electron- electron repulsion increases and more electrons are added to the atom while Z is held constant, the electron cloud size is increased. The size of the anion formed is usually measured as the size of this extended electron cloud. Hence the larger electron cloud means a larger anion size compared to the size of the neutral atom.

For a cation, the converse is true and the cation is found to be smaller than the neutral atom.

3 0

3 years ago

Read 2 more answers

Drag each label to the correct location on the table.

AleksAgata [21]

Explanation:

1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.

2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.

$V\propto T$ (At constant pressure and number of moles)

The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.

3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.

$V\propto n$ (At constant temperature and pressure)

When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.

3 0

3 years ago

What are the products in a neutralization reaction A. Two elements B.an acid and a base C. An element and a compound D. A salt a

frez [133]

D. Salt and water

Explanation:

Acid + Alkali -> Salt + water

5 0

2 years ago

Read 2 more answers