All categories

3 years ago

Answer number six please

Chemistry

2 answers:

soldier1979 [14.2K]3 years ago

7 0

the second one

forth one

and sixth one

victus00 [196]3 years ago

4 0

Ca^2+ (2nd one), Na+ (4th one), Cl- (5th one), S^2- (6th one)

You might be interested in

List the following elements from increasing electronegativity: boron, magnesium, calcium, chlorine, argon

pishuonlain [190]

Answer:

The list of elements from increasing electronegativity: Calcium < magnesium < chlorine < argon < boron.

Explanation:

In the periodic table if you move from left to right there would be an increase in the electronegativity of the elements. If you move from the bottom to the top of the groups in the periodic table the electronegativity increases and if u move to the bottom from down its decreases.

Calcium is in the 2nd group below magnesium so calcium is the least electronegative among given elements then magnesium and then chlorine as it is top of magnesium then argon, as it is right to the chlorine, and boron has the most electronegativity as it is above rest of the elements.

6 0

3 years ago

An ethylene glycol solution contains 21.4 g of ethylene glycol (C2H6O2) in 97.6 mL of water. (Assume a density of 1.00 g/mL for

8090 [49]

Answer: The freezing point and boiling point of the solution are $-6.6^0C$ and $101.8^0C$ respectively.

Explanation:

Depression in freezing point:

$T_f^0-T^f=i\times k_f\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_f$ = freezing point of solution = ?

$T^o_f$ = freezing point of water = $0^0C$

$k_f$ = freezing point constant of water = $1.86^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(0-T_f)^0C=1\times (1.86^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_f=-6.6^0C$

Therefore,the freezing point of the solution is $-6.6^0C$

Elevation in boiling point :

$T_b-T^b^0=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}$

where,

$T_b$ = boiling point of solution = ?

$T^o_b$ = boiling point of water = $100^0C$

$k_b$ = boiling point constant of water = $0.52^0C/m$

i = vant hoff factor = 1 ( for non electrolytes)

m = molality

$w_2$ = mass of solute (ethylene glycol) = 21.4 g

$w_1$ = mass of solvent (water) = $density\times volume=1.00g/ml\times 97.6ml=97.6g$

$M_2$ = molar mass of solute (ethylene glycol) = 62g/mol

Now put all the given values in the above formula, we get:

$(T_b-100)^0C=1\times (0.52^0C/m)\times \frac{(21.4g)\times 1000}{97.6g\times (62g/mol)}$

$T_b=101.8^0C$

Thus the boiling point of the solution is $101.8^0C$

4 0

3 years ago

Which term describes “one or more cells that carry out all of the processes needed to sustain life”?

Sergio039 [100]

Answer:

B. Organism

Explanation:

7 0

3 years ago

Read 2 more answers

the mass of a 125 cm3 piece of material is 82.75 g. determine the density of this material . please explain

andre [41]

You would do 82.75 divided by 125 cm3 and get 0.6620 g/cm3 because to find density you mist divide mass and volume and grams is always mass and cm3 or mL is always volume. hope i helped!

6 0

3 years ago

If you were to conduct an experiment to answer the question, "Does the volume of a caffeinated drink affect your reaction time?”

Ann [662]

Answer:

A Type of Drink

Explanation:

A controlled variable remains constant throughout the experiment.

In such experiment, you'd test the volume of one single caffeinated drink. You'd have to use the same type of drink every trial.

4 0

2 years ago