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icang [17]
3 years ago
15

Answer number six please

Chemistry
2 answers:
soldier1979 [14.2K]3 years ago
7 0

the second one

forth one

and sixth one


victus00 [196]3 years ago
4 0
Ca^2+ (2nd one), Na+ (4th one), Cl- (5th one), S^2- (6th one)
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The image shows particles of salt dissolved in water.
aalyn [17]

Answer:

Salt particles will diffuse and towards where it is less that is left !!

so your answer is A !! left through diffusion !!

Explanation:

6 0
3 years ago
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the main part of the microscope that is used to see and denlarge specimens what do you call this part?
Crazy boy [7]

Answer:

I believe you are asking about the objective lens or eyepiece.

Explanation:

Objective lenses are used to magnify objects enough for you to see them in great detail

Eyepiece/Ocular is what you look through at the top of the microscope.

A tube connects the eyepiece lens to objective lenses, which enhance the magnification power of the eyepiece lens. Both the eyepiece and the objective lens contribute to the magnification of the object.

The eyepiece lens usually magnifies 10x, and a typical objective lens magnifies 40x.

7 0
3 years ago
an ------ model with dark bands representing energy levels shows where an atoms electrons are most likely to be.
oksano4ka [1.4K]
Is it an atomic model? I'm not really sure
7 0
3 years ago
Using the example in the above information determine the empirical formula of a compound if a sample contains 0.130 g of nitroge
olga2289 [7]

Answer: The empirical formula for the given compound is NO_2

Explanation : Given,

Mass of O = 0.370 g

Mass of N = 0.130 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.370g}{16g/mole}=0.0231moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.130g}{14g/mole}=0.00928moles

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.00928 moles.

For Oxygen  = \frac{0.0231}{0.00928}=2.4\approx 2

For Nitrogen = \frac{0.00928}{0.00928}=1

Step 3: Taking the mole ratio as their subscripts.

The ratio of O : N = 2 : 1

Hence, the empirical formula for the given compound is NO_2

4 0
4 years ago
Match each state of matter to its description.
WARRIOR [948]

Answer:

Explanation:

solid would be a wall e.g

liquid would be water e.g

gas would be oxygen e.g

6 0
3 years ago
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