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UkoKoshka [18]
3 years ago
12

What prevents geologists from exploring earth's interior?

Physics
1 answer:
iren2701 [21]3 years ago
3 0
Maybe the Earth's core.
As it has high energy......
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Which vector below goes from (0,0) to (4,1)?
Lesechka [4]

Explanation:

Please attach the figure next to your question in order to help you.. Wish u the best and Have a great Day. Good Luck!

8 0
4 years ago
Please helpp this is due in 10 minutes?!!!!
Sati [7]

Answer:

1. at the top of the coaster.

2. at the bottom of the coaster.

3. when the car is moving

4. when the car is moving

Explanation:

there is the most amount if potential energy at the top, and the keast at the bottom.

5 0
3 years ago
Which of the following classifications of matter includes materials that can no longer be identified by their individual propert
lozanna [386]
The correct answer is B, I think

hope this helps
3 0
3 years ago
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Can someone please answer this, ill give you brainliest Would be very appreciated.
mina [271]

Water cycle basically involves the change of water into liquid to vapour and again to liquid states through a cyclic manner .

The answers are

  1. Evaporation
  2. Transpiration
  3. Condensation
  4. precipitation
  5. runoff
  6. seapage
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5 0
2 years ago
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In figure 1, charge q2 experiences no net electric force. What is q1?
lukranit [14]

By using Coulomb's law, we want to find the value of q₁ given that q₂ experiences no net electric force. We will find that q₁ = 8nC

<h3>Working with Coulomb's law.</h3>

Coulomb's law says that for two charges q₁ and q₂ separated by a distance r, the force that each one experiences is:

F = k\frac{q_1*q_2}{r^2}

Where k is a constant

Here we can see that q₂ interacts with two charges, then the total force on q₂ will be:

F = k\frac{q_1*q_2}{(20cm)^2} + k\frac{-2nC*q_2}{(10cm)^2}

And we know that it must be equal to zero, so we can write it as:

F = k\frac{q_1*q_2}{(20cm)^2} + k\frac{-2nC*q_2}{(10cm)^2} = 0\\\\k*q_2*(\frac{q_1}{(20cm)^2} + \frac{-2nC}{(10cm)^2}) = 0\\

The parenthesis must be equal to zero, so we can write:

\frac{q_1}{(20cm)^2} + \frac{-2nC}{(10cm)^2} = 0

And now we can solve this for q₁ to get:

q_1  = 2nC*(\frac{(20cm)^2}{(10cm)^2} ) = 8nC

If you want to learn more about Coulomb's law, you can read:

brainly.com/question/24743340

3 0
3 years ago
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