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AlladinOne [14]
4 years ago
14

Write five statements that can be identified as either observations or inferences.

Physics
1 answer:
Ivan4 years ago
7 0

Answer:

Examples are stated below.

Explanation:

Observation is simply when we make use of one or more of our sense to gather information while inference is simply the explanation/conclusion we make for what we observed.

Examples are as follows;

1) - Observation: There a lot of questions on google about the year 2021 being the end of the world.

Inference:

- Many people are just too lazy to do their own proper research.

2) - Observation: There is far more cold in the winter than in summer.

- Inference: Very little sunlight shines on the Earth's surface during the winter season.

3) - Observation: The fire alarm in the school is ringing.

-Inference: The school is burning

4) - Observation: The burglar alarm in the bank is ringing.

-Inference: Robbers have broken into the bank.

5) - Observation: The field in the school is very wet.

Inference: There was heavy Rainfall in the school.

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You can see a magnetic field of a magnet by using:
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Answer:

Option C

Explanation:

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3 years ago
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Radon-222 ( 222/86 Rn) is a radioactive gas with a half-life of 3.82 days. A gas sample contains 4.1 e 8 radon atoms initially.
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Answer :

(a) The number of radon atoms will remain after 12 days is, 4.67\times 10^7

(b) The number of radon nuclei have decayed by this time will be, 3.6\times 10^8

Explanation :

<u>For part (a) :</u>

Half-life = 3.82 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{3.82\text{ days}}

k=1.81\times 10^{-1}\text{ days}^{-1}

Now we have to calculate the number of radon atoms will remain after 12 days.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.81\times 10^{-1}\text{ days}^{-1}

t = time passed by the sample  = 12 days

a = initially number of radon atoms  = 4.1\times 10^8

a - x = number of radon atoms left = ?

Now put all the given values in above equation, we get

12=\frac{2.303}{1.81\times 10^{-1}}\log\frac{4.1\times 10^8}{a-x}

a-x=4.67\times 10^7

Thus, the number of radon atoms will remain after 12 days is, 4.67\times 10^7

<u>For part (b) :</u>

Now we have to calculate the number of radon nuclei will have decayed by this time.

The number of radon nuclei have decayed = Initial number of radon atoms - Number of radon atoms left

The number of radon nuclei have decayed = (4.1\times 10^8)-(4.67\times 10^7)

The number of radon nuclei have decayed = 3.6\times 10^8

Thus, the number of radon nuclei have decayed by this time will be, 3.6\times 10^8

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