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Natalka [10]
3 years ago
14

The lid on a jar is an example of which simple machine?

Chemistry
1 answer:
marysya [2.9K]3 years ago
8 0
Mechanical machine
poop on it
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Which term is used to describe the attraction that an oxygen atom has for the electrons in a chemical bond?
Mekhanik [1.2K]

electronegativty

It is the attraction force

8 0
3 years ago
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What is The atomic mass number of tin
san4es73 [151]

Answer:

50

Explanation:

The atomic number is 50

3 0
3 years ago
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What is the consecration of a solution that is made by diluting 50.0 mL of a 40.0 M NaCl solution to a final volume of 1000.0 mL
ira [324]

2M

Explanation:

Given that:

V1 = 50mL

M1 = 40M

V2 = 1000mL

unknown:

M2 = ?

Solution:

Concentration is the number of moles solute in a solution.

Since the number of moles in the solute remains the same;

   Concentration = \frac{number of moles}{volume}

number of moles = concentration x volume

 Number of moles before and after the dilution remains the same;

         M1 x V1 = M2 x V2

M1 is initial concentration

V1 is initial volume

M2 is final concentration

V2 is final volume

      40 x 50  = M2 x 1000

            M2 = 2M

learn more:

Molarity brainly.com/question/9324116

#learnwithBrainly

7 0
3 years ago
Determine the mass of each of t he following:
EastWind [94]

Explanation:

Mass of compounds = Moles of compound × Molecular mass of compound

a) Moles of LiCl = 2.345 mol

Molecular mass of LiCl = 42.5 g/mol

Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g

b) Moles of acetylene = 0.0872 mol

Molecular mass of acetylene= 26 g/mol

Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g

c) Moles of sodium carbonate= 3.3\times 10^{-2}mol

Molecular mass of sodium carbonate= 106 g/mol

Mass of  3.3\times 10^{-2}mol sodium carbonate

=  3.3\times 10^{-2}mol\times 106 g/mol= 3.498 g

d) Moles of fructose = 1.23\times 10^3 mol

Molecular mass fructose= 180 g/mol

Mass of  1.23\times 10^3 mol fructose

=  1.23\times 10^3mol\times 180 g/mol = 221,400 g

e) Moles of  FeSO_4(H_2O)_7=0.5758 mol

Molecular mass of FeSO_4(H_2O)_7 =278 g/mol

Mass of  1.23\times 10^3 mol fructose

=  0.5758 mol\times 278 g/mol= 160.0724 g

3 0
3 years ago
[15 Points, Stoichiometry and Gases]
KiRa [710]

The reaction is

CaC₂(s) + 2H₂O (l) -----> Ca(OH)₂ (s) + C₂H₂ (g) ​

As we have data of gas ethyne (or acetylene), C₂H₂

We can calculate the moles of acetylene and from this we can estimate the mass of calcium carbide taken

the moles of acetylene will be calculated using ideal gas equation

PV =nRT

R = gas constant = 0.0821 Latm/molK

T = 385 K

V = volume = 550 L

P = Pressure = 1.25 atm

n = moles = ?

n = PV /RT = 1.25 X 550 / 0.0821 X 385 = 21.75 mol

As per balanced equation these moles of acetylene will be obtained from same moles of calcium carbide

moles of calcium carbide = 21.75mol

molar mass of CaC₂ = 40 + 24 = 64

mass of CaC₂ = moles X molar mass = 21.75 X 64 = 1392g

6 0
4 years ago
Read 2 more answers
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