Let us assume that there is a 100g sample of Opal. The masses of each element will be:
29.2g Si
33.3g O
37.5g H2O
Now we divide each constituent's mass by its Mr to get the moles present
Si: (29.2 / 28) = 1.04
O: (33.3 / 16) = 2.08
H2O: (37.5 / 18) = 2.08
Now we divide by the smallest number and obtain:
Si: 1
O: 2
H2O: 2
Thus, the empirical formula of Opal is:
SiO2 . 2H2O
Answer:
- 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)
- 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
- 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
- 2a) Calcium hydroxide and hydrogen gas
- 2b) Tin(II) silicate and Lead(IV) permanganate
- 2c) Magnesium oxide and water
- 2f) Calcium chloride and iodine
- 2g) Strontium phosphite and cesium nitride
- 2h) Carbon dioxide, water, and sulfur dioxide
- 2i) Iron oxide(III) and carbon dioxide
- 2j) Magnesium acetate and hydrogen gas
Explanation:
1. For each of the following, convert the word equation into a formula equation, BUT do not balance!
a) Barium chlorate → Barium chloride + Oxygen
<u>1. Chemical formulas</u>
Barium chlorate:
- It is a salt: an ionic compound.
- Barium has oxidation state +2
- Chlorate is the ion ClO₃⁻
- Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
- Chemical formula Ba(ClO₃)₂
- It is solid: Ba(ClO₃)₂(s)
Barium chloride:
- It is a salt: an ionic compount
- Barium has oxidation state +2
- Chlorine is in oxidation state -1
- Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
- BaCl₂
- It is solid BaCl₂(s)
Oxygen:
- It is a diatomic gas molecule
- O₂(g)
<u />
<u>2. Write the unbalanced molecular equation:</u>
- BaClO₃(s) → BaCl₂(s) + O₂(g)
b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride
<u>1. Chemical formulas</u>
Chlorine:
- It is a diatomic gas molecule
- Cl₂(g)
Potassum nitride
- Potassium has oxidation state +1
- Nitrogen is with oxidation state +3
- Swap the oxidation states
- K₃N
- It is solid: K₃N(s)
Nitrogen:
- It is a diatomic gas
- N₂(g)
Potassium chloride
- It is a salt (ionic compound)
- Potassium has oxidation state +1
- Chlorine is in oxidation state -1
- Swap the oxidation numbers
- KCl
- It is solid: KCl(s)
<u>2. Write the unbalanced molecular equation</u>
<u />
- Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)
c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate
<u>1. Chemical formulas</u>
Sodium nitride
- It is a salt (ionic compound)
- Sodium has oxidation state +1
- Nitrogen is with oxidation state -3
- Swap the oxidation numbers
- Na₃N
- It is in aqueous solution
- Na₃N (aq)
Aluminum bromate
- Salt
- Aluminum has oxidation state +3
- Bromate is the ion BrO₃⁻
- Swap the oxidation states
- Al(BrO₃)₃ (aq)
Aluminum nitride
- Both Al and N have oxidation state 3, which simply
- AlN(s). It is not soluble in water.
Sodium bromate
<u>2. Write the unbalanced molecular equation</u>
- Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)
<h2>
This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2>
</h2><h2>
The attached file contains the complete answer.</h2>
8 moles of water on the right side.
An oxidation-reduction or redox reaction is a reaction that involves the transfer of electrons between chemical items (the atoms, ions, or molecules involved in the reaction).
Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.
Step 1:
MnO4- ----> Mn2+
2Cl- ------> Cl2
Step 2:
MnO4- --> Mn2+ + 4H2O
2Cl- -----> Cl2
Step 3:
8H+ + MnO4- ------> Mn2+ + 4H2O
2Cl- ----->Cl2
Step 4:
8H+ + MnO4- +5e- ------>Mn2+ + 4H2O
2Cl- ----> Cl2+ 2e-
Step 5:
16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2
This is the balanced equation in an acidic medium.
That is 8, right side.
To know more about redox reaction follow the link:
https://brainly.in/question/9854479
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Noble Gases is the answer. These elements have a full outer shell composed of eight valence electrons, meaning that they do not need to gain electrons from other elements in reactions, making them nonreactive (inert).
A. Li also know as Lithium has 3 protons.
B. To find number of neutrons in a element you subtract number of protons by mass number.
C. Protons have a positive charge.
D. Electrons have a negative charge.
E. Neutrons have no charge and are neutral.
