2C5H12 + 16O2 —> 10CO2 + 12H2O
2•5=10 C 10=1•10
2•12=24 H 24=2•12
16•2=32 O 32=(10•2)+(1•12)
=20+12
Answer:
C
Explanation:
Melting point, temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.
i. The dissolution of PbSO₄ in water entails its ionizing into its constituent ions:

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ii. Given the dissolution of some substance
,
the Ksp, or the solubility product constant, of the preceding equation takes the general form
.
The concentrations of pure solids (like substance A) and liquids are excluded from the equilibrium expression.
So, given our dissociation equation in question i., our Ksp expression would be written as:
.
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iii. Presumably, what we're being asked for here is the <em>molar </em>solubility of PbSO4 (at the standard 25 °C, as Ksp is temperature dependent). We have all the information needed to calculate the molar solubility. Since the Ksp tells us the ratio of equilibrium concentrations of PbSO4 in solution, we can consider either [Pb2+] or [SO4^2-] as equivalent to our molar solubility (since the concentration of either ion is the extent to which solid PbSO4 will dissociate or dissolve in water).
We know that Ksp = [Pb2+][SO4^2-], and we are given the value of the Ksp of for PbSO4 as 1.3 × 10⁻⁸. Since the molar ratio between the two ions are the same, we can use an equivalent variable to represent both:

So, the molar solubility of PbSO4 is 1.1 × 10⁻⁴ mol/L. The answer is given to two significant figures since the Ksp is given to two significant figures.
The average atomic mass in amu of element X is 58.42 amu
The average atomic mass is the sum of the mass number of each of the isotopes multiplied by their respective abundances.
So;
The average atomic mass of element X is;
(58 * 0.68) + (60 * 0.26) + (0.06 * 62)
= 39.44 + 15.26 + 3.72
= 58.42 amu
The average atomic mass in amu of X is 58.42 amu.
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The rectangular substance measures 3.60cm high, 4.21cm long, and 1.17cm wide. If the mass is 21.3g substances density will be 1.20 centimeter cube.
<h3>What is density?</h3>
The density of any substance is the ratio of the mass of substance to the volume of the substance and the unit will be centimeter cube.
The volume of the substance will be 3.60cm high × 4.21cm long ×1.17cm wide = 17.7 milliliters.
density = mass of substance / volume of substance
Substituting the value in formula
Density = 21.3g / 17.7 milliliters.
Density = 1.20 centimeter cube.
Therefore, rectangular substance measures 3.60cm high, 4.21cm long, and 1.17cm wide. If the mass is 21.3g substances density will be 1.20 centimeter cube.
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