Answer:
2H+ + 2e - ---> H2(g) is the cathode
2Cl - ---> Cl2(g) + 2e - is the anode
Explanation:
Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.
Answer:
I think it is b. B (Atomic No. 17)
Answer:
11.43g of Aluminum Hydroxide
Explanation:
Since we know that the sulfuric acid is the limiting reactant in this chemical reaction, we know that we are going to be left with excess aluminum hydroxide. So to find the amount of leftover aluminum hydroxide we are going to need to convert the given amount of sulfuric acid to the amount of aluminum hydroxide needed to react with the sulfuric acid.

Once you do that, you need to subtract that number from the amount of aluminum hydroxide given to get the amount of left over aluminum hydroxide.

Hope this helps!
Answer:
CuO with (1: 1) mole ratio.
Explanation:
- When 6.1 moles of copper react completely with 6.1 moles of oxygen.
- They are equimole reactants with a (1: 1) mole ratio.
- Then, the compound has the molecular formula CuO.