Answer:
540 nm
Explanation:
According to the question,
The refractive index of the soap bubble,
.
The thickness of the soap bubble wall is,
.
Now, for constructive interference of soap bubble.
.
Now for first order m=1.
Therfore,

Substitute all the variables in the above equation.
.
Therefore,
.
Therefore the visible light wavelength which is strongly reflected is 540 nm.
A. The acceleration during the slide is 6.86 m/s²
B. The time taken to slide until he stops is 1.2 s
<h3>How to determine the force of friction</h3>
- Mass (m) = 81.5 Kg
- Coefficient of friction (μ) = 0.7
- Acceleration due to gravity (g) = 9.8 m/s²
- Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 N
- Frictional force (F) =?
F = μN
F = 0.7 × 798.7
F = 559.09 N
<h3>A. How to determine the acceleration</h3>
- Mass (m) = 81.5 Kg
- Frictional force (F) = 559.09 N
- Acceleration (a) =?
a = F / m
a = 559.09 / 81.5
a = 6.86 m/s²
<h3>B. How to determine the time </h3>
- Initial velocity (u) = 8.23 m/s
- Final velocity (v) = 0 m/s
- Decceleration (a) = -6.86 m/s²
- Time (t) =?
a = (v – u) / t
t = (v – u) / a
t = (0 – 8.23) / -6.86
t = 1.2 s
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Answer:
1. Can change the state of an object(rest to motion/ motion to rest)
2. May change the speed of an object if it is already moving.
3. May change the direction of motion of an object.
Explanation: A force acting on an object causes the object to change its shape or size, to start moving, to stop moving, to accelerate or decelerate.
The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 *
C
Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.
Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.
charge = capacitance * voltage
Q = CV
= 3 *
* 15 v
= 45 *
C
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