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2 years ago

Name a chemical that she may use to control this disease

Physics

2 answers:

katrin2010 [14]2 years ago

6 0

Answer:

antisipict -that protact from disese

Deffense [45]2 years ago

3 0

Answer:

Explanation:

Antiseptics, or skin disinfectants, are chemicals for cleaning the skin and wounds. They can kill or prevent the growth of microorganisms.

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Zigmanuir [339]

Answer:

it’s 2.5 m/s

Explanation:

i’m too lazy but trust

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2 years ago

How can you find the net force if two forces act in opposite directions?

Tresset [83]

Then the magnitude of the net force is the difference between the two forces,
and its direction is the same as the direction of the greater one.

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2 years ago

Is the expression "The bigger they are, the harder they fall" a generally true statement since, in the absence of air resistance

lions [1.4K]

No, because in oxygen depraved rooms, if you drop a feather and a bowling ball at the same height and time, they will fall at the same speed and have the same amount of impact.

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3 years ago

Read 2 more answers

If the density of a substance is 5g/cm3 and the volume is 10cm3,<br> determine the mass.

vaieri [72.5K]

Answer:

(5g/cm³)*(10cm³) = 50g

Explanation:

This is just a conversion formula. Easy to find using dimensional analysis.

(5g/cm³)*(10cm³) = 50g

6 0

2 years ago

Read 2 more answers

A muon has a rest mass energy of 105.7 MeV, and it decays into an electron and a massless particle. If all the lost mass is conv

sergeinik [125]

Answer:

The electron’s velocity is 0.9999 c m/s.

Explanation:

Given that,

Rest mass energy of muon = 105.7 MeV

We know the rest mass of electron = 0.511 Mev

We need to calculate the value of γ

Using formula of energy

$K_{rel}=(\gamma-1)mc^2$

$\dfrac{K_{rel}}{mc^2}=\gamma-1$

Put the value into the formula

$\gamma=\dfrac{105.7}{0.511}+1$

$\gamma=208$

We need to calculate the electron’s velocity

Using formula of velocity

$\gamma=\dfrac{1}{\sqrt{1-(\dfrac{v}{c})^2}}$

$\gamma^2=\dfrac{1}{1-\dfrac{v^2}{c^2}}$

$\gamma^2-\gamma^2\times\dfrac{v^2}{c^2}=1$

$v^2=\dfrac{1-\gamma^2}{-\gamma^2}\times c^2$

Put the value into the formula

$v^2=\dfrac{1-(208)^2}{-208^2}\times c^2$

$v=c\sqrt{\dfrac{1-(208)^2}{-208^2}}$

$v=0.9999 c\ m/s$

Hence, The electron’s velocity is 0.9999 c m/s.

6 0

2 years ago

Name a chemical that she may use to control this disease​

Name a chemical that she may use to control this disease