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Karo-lina-s [1.5K]
3 years ago
9

Any one tell me about the earth rotation it rotatining or not with any proof? ​

Physics
1 answer:
Dafna11 [192]3 years ago
6 0
The proof that the earth is rotating is the happens of night and day also the seasons, eg. winter, summer, autumn.
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A family leaves home at 1:00pm and arrives at their vacation spot 200 miles away at 5:00pm on the same day. What is their averag
Shkiper50 [21]
The answer is 40 because you just have to do 200 divided by 5
4 0
3 years ago
Interrelationship between health population and environment education and Science and Technology​
S_A_V [24]

Answer:

Answer: Science and technology are relatively modern developments. For most of the past 50,000 years of civilization, there was religion, dogma, ritual an tradition. These kept civilization safe but prevented growth.

After the modern scientific method was developed during the Rennaisance, civil action took off.

Health, as expressed as life expectancies, has increased massively. Population growth has increased to levels thought impossible before. But yes, the environment has suffered.

8 0
4 years ago
A playground ride requires 21 seconds to make one complete revolution
luda_lava [24]

The angular speed of the playground ride is determined as 0.3 rad/s.

<h3>What is angular speed?</h3>

Angular speed is the rate at which an object changes it angles which we measure in radians in a given time.

<h3>Angular speed of the ride</h3>

The angular speed of the ride if the ride makes one complete revolution is calculated as follows;

ω = θ/t

ω = 2π/t

where;

  • ω is angular speed of the ride
  • t is time of motion of the ride

one complete revolution = 2π radians

ω = 2π/21

ω = 0.3 rad/s

Thus, the angular speed of the playground ride is determined as 0.3 rad/s.

Learn more about angular speed here: brainly.com/question/24158647

#SPJ1

The complete question is below;

A playground ride requires 21 seconds to make one complete revolution, what is angular speed of the ride in radian per second.

3 0
2 years ago
Find f0, the magnitude of the upward force on the table due to the leg at (0, 0.
Katena32 [7]
Assuming that the table has 4 legs. the upward force is equal to the downwardd force. the downward force of the table is the weight of the table. so the upward force is also the weight of the table but in opposite direction, so the upward force in on one leg is 1/4 of the weight of the table
6 0
4 years ago
Eld a distance r1 from P. The second particle is then released. Determine its speed when it is a distance r2 from P. Let q = 3.1
zheka24 [161]

Answer:

v_{f}=1721.1m/s

Explanation:

Given data

q = 3.1 µC

m = 47 mg

r1 = 0.83 mm

r2 = 2.5 mm.

As we know that:

dK=-dU\\(1/2)mv_{f}^{2}-(1/2)mv_{i}^{2}=-(\frac{kq^{2} }{r_{f}}-\frac{kq^{2} }{r_{i}} )\\    (1/2)*(47*10^{-6}kg )v_{f}^{2}-(1/2)*(47*10^{-6}kg)(0)=-[(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{2.5*10^{-3}}-(\frac{(9*10^{9}(3.1*10^{-6})^{2}  }{0.83*10^{-3}} )]\\2.35*10^{-5} v_{f}^{2}=69.61\\v_{f}=\sqrt{\frac{69.61}{2.35*10^{-5}} }\\v_{f}=1721.1m/s

5 0
3 years ago
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