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morpeh [17]
4 years ago
13

People, such as pilots, who have to move quickly from lighted surroundings to night

Physics
1 answer:
sergey [27]4 years ago
7 0

Answer:

the rods are insensitive to red light.​

Explanation:

People, such as pilots, who have to move quickly from lighted surroundings to night darkness use red light illumination because human eye is less sensitive to longer wavelength ( rhodopsin in rods cells of eye).Using red goggles,the cones can receive enough light to provide photopic vision. Whereas rods are less sensitive to longer wavelength (red light).So, the crew members remains dark adopted.

Hence, (d) is the correct answer.

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The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and
nikitadnepr [17]

Complete question:

The exit nozzle in a jet engine receives air at 1200 K, 150 kPa with negligible kinetic energy. The exit pressure is 80 kPa, and the process is reversible and adiabatic. Use constant specific heat at 300 K to find the exit velocity.

Answer:

The exit velocity is 629.41 m/s

Explanation:

Given;

initial temperature, T₁ = 1200K

initial pressure, P₁ = 150 kPa

final pressure, P₂ = 80 kPa

specific heat at 300 K, Cp = 1004 J/kgK

k = 1.4

Calculate final temperature;

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}

k = 1.4

T_2 = T_1(\frac{P_2}{P_1})^{\frac{k-1 }{k}}\\\\T_2 = 1200(\frac{80}{150})^{\frac{1.4-1 }{1.4}}\\\\T_2 = 1002.714K

Work done is given as;

W = \frac{1}{2} *m*(v_i^2 - v_e^2)

inlet velocity is negligible;

v_e = \sqrt{\frac{2W}{m} } = \sqrt{2*C_p(T_1-T_2)} \\\\v_e = \sqrt{2*1004(1200-1002.714)}\\\\v_e = \sqrt{396150.288} \\\\v_e = 629.41  \ m/s

Therefore, the exit velocity is 629.41 m/s

6 0
3 years ago
At what time were the racers at the same position?<br> O 15<br> O 3s<br> O 5s<br> 0 4s
Jlenok [28]
The Answer is:

O 3s

Hope you got it right.
5 0
3 years ago
Read 2 more answers
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zloy xaker [14]

The imaginary second level is 60 dB more intense than the real level of the caller.

60 dB means a multiplication of  10⁶  = <em>1 million.</em>

That's how many equally-talented callers it would take to be 60 dB louder than him.

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3 years ago
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kotegsom [21]

Answer:

4) Coefficent in science

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4 years ago
I need some help with my science homework about energy, work, and power. It would be greatly appreciated :)
fgiga [73]

Answer:

1. B

Explanation:

Work = Force × Distance

Work = 4N × 1.5M

5 0
4 years ago
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