Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
alloy that contains 25 wt% Au and 75 wt% Ag. The densities of pure gold and silver are 19.32 and 10.49 g/cm3, respectively. The atomic weight of Au is 196.97 g/mol.
1 answer:
Answer:
Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3
Explanation:
The step by step and appropriate substitution is as shown in the attachment.
From number of moles = Concentration x volume
number of moles = number of particles/ Avogadro's number
Volume = mass/density, the appropriate derivation to get the number of moles of atoms
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Answer:
(a) maximum positive reaction at A = 64.0 k
(b) maximum positive shear at A = 32.0 k
(c) maximum negative moment at C = -540 k·ft
Explanation:
Given;
dead load Gk = 400 lb/ft
live load Qk = 2 k/ft
concentrated live load Pk =8 k
(a) from the influence line for vertical reaction at A, the maximum positive reaction is
= 2*(8) +(1/2(20 - 0)* (2))*(2 + 0.4) = 64 k
See attachment for the calculations of (b) & (c) including the influence line
