Gold forms a substitutional solid solution with silver. Compute the number of gold atoms per cubic centimeter for a silver-gold
alloy that contains 25 wt% Au and 75 wt% Ag. The densities of pure gold and silver are 19.32 and 10.49 g/cm3, respectively. The atomic weight of Au is 196.97 g/mol.
1 answer:
Answer:
Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3
Explanation:
The step by step and appropriate substitution is as shown in the attachment.
From number of moles = Concentration x volume
number of moles = number of particles/ Avogadro's number
Volume = mass/density, the appropriate derivation to get the number of moles of atoms
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Answer:
77.2805 μF
Explanation:
Given data :
V = 2460 V
Q = 191 Kva
<u>Calculate the size of Each capacitor </u>
first step : calculate for the value of Xc
Q = V^2/ Xc
Xc ( capacitive reactance ) = V^2 / Q = 2460^2 / ( 191 * 10^3 ) = 31.683 Ω
Given that 1 / 2πFc = 31.683
∴ C ( size of each capacitor ) = = 77.2805 μF
Answer:
Explanation:
solution to the question
