All categories

3 years ago

What is the horizontal distance from Point A to toe of slope?

Engineering

1 answer:

Nezavi [6.7K]3 years ago

4 0

Answer:

2.467 units

Explanation:

$Slope=\frac {\triangle y}{\triangle x}$

Therefore, slope being change in vertical to change in horizontal, we need to find the change in vertical

Change in vertical, $\triangle y=98.2-94.5=3.7$

$\frac {1 1/2}{1}=\frac {3.7}{\triangle x}$

$\triangle x=\frac {3.7\times 1}{1 1/2}\approx 2.467 units$

You might be interested in

A bridge hand consists of 13 cards. One way to evaluate a hand is to calculate the total high point count (HPC) where an ace is

son4ous [18]

Answer: Let us use the pickled file - DeckOfCardsList.dat.

Explanation: So that our possible outcome becomes

7♥, A♦, Q♠, 4♣, 8♠, 8♥, K♠, 2♦, 10♦, 9♦, K♥, Q♦, Q♣

HPC (High Point Count) = 16

4 0

2 years ago

Question 4 (1 point) Sophia is working in her garden. She made two trips with her wagon along the same path to haul supplies. Th

yaroslaw [1]

Answer:

Option A

Explanation:

Please find the attachment

4 0

2 years ago

Explain The Basic Difference Between Bs2 And Bs3 Engine.

snow_tiger [21]

Answer:

The main difference between the bs2 and bs3 engine is to present in the catalytic converter. And in bs2 engines the catalytic converter is does not used for the formation of hc and co. In bs3 engine there is no harmful emissions in the hc and co

3 0

2 years ago

A work element in a manual assembly task consists of the following MTM-1 elements: (1) R16C, (2) G4A, (3) M10B5, (4) RL1, (5) R1

ella [17]

Answer:

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b) 3.1 secs

Explanation:

a) Determine the normal times in TMUs for these motion elements

1) R16C ; Tn = 17 TMU

2) G4A ; Tn = 7.3 TMU

3) M10B5 ; Tn = 15.1 TMU

4) RL1 ; Tn = 2 TMU

5) R14B ; Tn = 14.4 TMU

6) G1B ; Tn = 3.5 TMU

7) M8C3 ; Tn = 14.7 TMU

8) P1NSE ; Tn = 10.4 TMU

9) RL1 ; Tn = 2 TMU

b ) Determine the total time for this work element in seconds

first we have to determine the total TMU = ∑ TMU = 86.4 TMU

note ; 1 TMU = 0.036 seconds

hence the total time for the work in seconds = 86.4 * 0.036 = 3.1 seconds

7 0

2 years ago

Imagine the reaction A + B LaTeX: \Longleftrightarrow⟺ C + D proceeds at room temperature (25 °C) and is determined to have a re

Wittaler [7]

Answer:

0.2 kcal/mol is the value of $\Delta G$ for this reaction.

Explanation:

The formula used for is:

$\Delta G_{rxn}=\Delta G^o+RT\ln Q$

$\Delta G^o=-RT\ln K$

where,

$\Delta G_{rxn}$ = Gibbs free energy for the reaction

$\Delta G_^o$ = standard Gibbs free energy

R =Universal gas constant

T = temperature

Q = reaction quotient

k = Equilibrium constant

We have :

Reaction quotient of the reaction = Q = 46

Equilibrium constant of reaction = K = 35

Temperature of reaction = T = 25°C = 25 + 273 K = 298 K

R = 1.987 cal/K mol

$\Delta G_{rxn}=-RT\ln K+RT\ln Q$

$=-1.987 cal/K mol\times 298 K\ln [35]+1.987 cal/K mol\times 298K\times \ln [46]$

$=-2,105.21 cal/mol+2,267.04 cal/mol=161.82 cal/mol=0.16182 kcal/mol\approx 0.2 kcal/mol$

1 cal = 0.001 kcal

0.2 kcal/mol is the value of $\Delta G$ for this reaction.

5 0

2 years ago