Answer:
46 cm
Step-by-step explanation:
Let p represent the length in cm of 1 bap'ai; let k represent the length in cm of 1 bok'ai. Then we have ...
12p +2k = 100
10p +10k = 100
Subtracting the second equation from 5 times the first, we get ...
5(12p +2k) -(10p +10k) = 5(100) -(100)
50p = 400
p = 8 . . . . cm
Then the second equation tells us ...
10(8) +10k = 100
10k = 20
k = 2 . . . . cm
Then 5p+3k = 5(8) +3(2) = 46 cm.
The distance 5 bap'ai and 3 bok'ai is 46 cm.
Can you rephrase it? (maybe write it out in numbers?)
Answer:
3.56m
Step-by-step explanation:Parameters given:
Area of the rectangular garden = 16.02m^2
Length of the rectangular garden = 4.5m
The Area of a rectangle can be calculated for using the formula below
Area (square meters) = length (meters) × width (meters)
Therefore, 16.02m^2 = 4.5m × width
Width = 16.02m^2 / 4.5m
Width = 3.56m
Therefore the width in meters of the garden is 3.56m
See the attachment below for an illustrative diagram
A = area
l = length
w = width
6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer should be 1.85 x 10^18
