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lana66690 [7]
3 years ago
13

Which condition is characterized by the typical display of rigid behaviors that make it difficult for a person to get along with

others
Physics
1 answer:
Viktor [21]3 years ago
5 0
The answer being described above is MOOD DISORDERS. This is the condition that usually shows rigid behaviors which make it hard for the person to socialize with others. When a person is suffering from mood disorders, he or she has frequent mood changes, which hinders them to effectively get along with others. One of the most common example of a mood disorder is the major depressive disorders wherein a person experiences long term sadness.
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If an electric wire is allowed to produce a magnetic field no larger than that of the Earth (0.503 X 104 T) at a distance of 15
dem82 [27]

Answer:

37.725 A

Explanation:

B = magnitude of the magnetic field produced by the electric wire = 0.503 x 10⁻⁴ T

r = distance from the wire where the magnetic field is noted = 15 cm = 0.15 m

i = magnitude of current flowing through the wire = ?

Magnetic field by a long wire is given as

B = \frac{\mu _{o}}{4\pi }\frac{2i}{r}

Inserting the values

0.503\times 10^{-4} = (10^{-7})\frac{2i}{0.15}

i = 37.725 A

6 0
3 years ago
A long, straight wire carrying a current of 2.60 A is placed along the axis of a cylinder of radius 0.500 m and a length of 4.25
shutvik [7]
<h2>Answer:</h2>

0

<h2>Explanation:</h2>

Since the current carrying wire is placed along the axis of the cylinder, according to the right hand rule, the magnetic field will be tangent to the surface of the cylinder. Therefore, there is no magnetic field through the cylinder.

Remember that the magnetic flux through a given area is the total magnetic field passing through that area. Since there is not magnetic field through the cylinder, the total magnetic flux is therefore zero (0).

7 0
3 years ago
7–¹ plsss pa answer mga lods​
Rasek [7]
Amigo no se lo que ablas
3 0
3 years ago
Standing at a crosswalk, you hear a frequency of 530 Hz from the siren of an approaching ambulance. After the ambulance passes,
malfutka [58]

Answer:

_s = 37.77 m / s

Explanation:

This is an exercise of the Doppler effect that the change in the frequency of the sound due to the relative speed of the source and the observer, in this case the observer is still and the source is the one that moves closer to the observer, for which relation that describes the process is

                    f ’= f₀  \frac{v}{v - v_s}

where d ’= 530 Make

when the ambulance passes away from the observer the relationship is

                    f ’’ = f₀ \frac{v}{v + v_s}

where d ’’ = 424 beam

let's write the two expressions

               f ’ (v-v_s) = fo v

               f ’’  (v + v_s) = fo v

let's solve the system, subtract the two equations

                v (f ’- f’ ’) - v_s (f’ + f ’’) = 0

                v_s = v \frac{ f' - f''}{ f' + f''}

the speed of sound is v = 340 m / s

let's calculate

                 v_s = 340 (\frac{ 530 -424}{530+424} )

                 v_s = 340 (\frac{106}{954})

                  v_s = 37.77 m / s

5 0
3 years ago
A small smooth object slides from rest down a smooth inclined plane inclined at 30degrees horizontal.What is the acceleration do
asambeis [7]
The acceleration is given as:

a = g sin(30°) where g is the gravitational acceleration

For g = 10 m/s^2, we get

a = 10 sin(30°) = 10 * 1/2 = 5 m/s^2
7 0
3 years ago
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