The correct answer to the question above is that the magician is seeking the wavelength of the standing wave. The part of a standing sound wave, which is its wavelength, the magician is seeking when playing a musical note of a specific pitch.

6 0

3 years ago

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El aspa de un ventilador de 0.30 m de diametro gira 1200 rev/min. calcule la rapidez tangencial.

Keith_Richards [23]

Answer:

v = 18.84 m/s

Explanation:

Let the question says,"The blade of a 0.30 m diameter fan rotates 1200 rev / min. calculate the tangential speed."

It is given that,

Diameter of a blade of fan is 0.3 m

Angular velocity of the fan is 1200 rev/min or 125.66 rad/s

We need to find the tangential speed of the fan. The relation is given by :

$v=r\omega$

r is radius of fan

$v=0.15\times 125.66 \\\\v=18.84\ m/s$

So, the tangential velocity is 18.84 m/s.

4 0

3 years ago

You drop a rock off the top of a 100m tall building. How long does it take to hit the ground?

frutty [35]

How heavy is the rock? comment and i will tell you answer

3 0

3 years ago

Objects of equal mass are oscillating up and down in simple harmonic motion on two different vertical springs. The spring consta

Zanzabum

Answer:

$k_2=920\ N/m$

Explanation:

Given that,

The spring constant of spring 1, $k_1=230\ N/m$

The motion of the object on spring 1 has twice the amplitude as the motion of the object on spring 2, $A_1=2A_2$

As the magnitude of the maximum velocity is the same in each case, it means the maximum kinetic energy is same in each case. In other words, the total energy is same.

$\dfrac{1}{2}k_1A_1^2=\dfrac{1}{2}k_2A_2^2$

$k_1A_1^2=k_2A_2^2$

$k_1(2A_2)^2=k_2A_2^2$

$k_2=920\ N/m$

So, the spring constant of spring 2 is 920 N/m. Hence, this is the required solution.

3 0

3 years ago