W=K_B-K_A
W=m_B v^2/2-m_A v^2/2=(m_B-m_A)v^2/2
W=(2000-1200) 〖40〗^2/2=640000 J=640 kJ.
Answer:
It is generally customary in a free-body diagram to represent the object by a box and to draw the force arrow from the center of the box outward in the direction that the force is acting. An example of a free-body diagram is shown at the right. T he free-body diagram above depicts four forces acting upon the object.
Explanation:
Answer:
Explanation:
<u>Mechanical Force</u>
According to the second Newton's law, the net force F exerted by an external agent on an object of mass m is:
F = m.a
Where a is the acceleration of the object.
Assume we apply some given force F to an object of m1=1 Kg that produces an acceleration , then:
F = m1.a1
The same force F is now applied to a second object m2=4 Kg that produces an acceleration a2, then:
F = m2.a2
Dividing both equations:
Solving for a2:
Substituting values:
The object is maintaining a constant velocity
Answer:
sorry I don't really know about that question.
Explanation: