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Alex Ar [27]
2 years ago
11

Two students have fitted their scooters with the same engine. Student A and his

Physics
1 answer:
sammy [17]2 years ago
3 0

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

  • m is mass
  • a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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When two waves meet they combine according to the ____________________ principle?
larisa [96]
The answer that would best complete the given statement above would be the term SUPERPOSITION. Here is the complete statement. <span>When two waves meet they combine according to the superposition principle. Hope this answers your question. Have a great day ahead!</span>
3 0
3 years ago
Rahul runs a distance of 12
Radda [10]

Answer:

Rita runs faster

Explanation:

To obtain the answer to the question given, we determine the speed of Rita. This can be obtained as follow:

Distance = 1.6 km

Time = 15 mins

Speed =?

Next, we shall convert 15 mins to hour. This can be obtained as follow:

60 mins = 1 h

Therefore,

15 mins = 15 mins × 1 h / 60 mins

15 mins = 0.25 h

Thus, 15 mins is equivalent to 0.25 h.

Finally, we shall determine speed of Rita as follow:

Distance = 1.6 km

Time = 0.25 h

Speed =?

Speed = distance / time

Speed = 1.6 / 0.25

Speed = 6.4 Km/h

Thus Rita's speed is 6.4 Km/h

Comparing the speed of Rahul and Rita

Rahul's speed = 4.5 km/h

Rita's speed = 6.4 Km/h

We can see that Rita's speed is greater than Rahul's speed. This simply indicates that Rita runs faster than Rahul.

4 0
3 years ago
Richard is driving home to visit his parents. 135{\rm mi} of the trip are on the interstate highway where the speed limit is 65{
nydimaria [60]

Answer:

time spent = 0.2276

Explanation:

given data

distance = 135 mi

usual speed = 65 mph

today speed = 73 mph

solution

we get here time that is express as

time = \frac{distance}{speed}    ...................1

usual time = \frac{135}{65}  = 2.0769 h

today time = \frac{135}{73} = 1.8493 h

so we get here time spent as

time spent = 2.0769 h - 1.8493 h

time spent = 0.2276

6 0
4 years ago
what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan spe
ArbitrLikvidat [17]

Explanation:

The attached figure shows data for the cart speed, distance and time.

For low fan speed,

Distance, d = 500 cm

Time, t = 7.4 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2

For medium fan speed,

Distance, d = 500 cm

Time, t = 6.4 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2

For high fan speed,

Distance, d = 500 cm

Time, t = 5.6 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2

Hence, this is the required solution.

8 0
3 years ago
Read 2 more answers
A 3.00 kg block moving 2.09 m/s
Talja [164]

Answer:11.64kgm/s

Explanation:

4 0
3 years ago
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