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Alex Ar [27]
2 years ago
11

Two students have fitted their scooters with the same engine. Student A and his

Physics
1 answer:
sammy [17]2 years ago
3 0

The force exerted by student A with his scooter is 306 N and that of student B is 204 N.

<h3>Force applied by each student</h3>

The force exerted by each student is calculated from Newton's second law of motion.

F = ma

where;

  • m is mass
  • a is acceleration

F(A) = 127.5 x 2.4

F(A) = 306 N

F(B) = 120 x 1.7

F(B) = 204 N

Thus, the force exerted by student A with his scooter is 306 N and that of student B is 204 N.

Learn more about force here: brainly.com/question/12970081

#SPJ1

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A man with his eye level 6 feet above the ground is standing 3 feet away from the base of a 15-foot vertical ladder. If he looks
DochEvi [55]

Answer:

Answer:

71.6°

Explanation:

According to the diagram

ED = 6 feet

DA = EB = 3 feet

AC = 15 feet

AB = ED = 6 feet

BC = AC - AB = 15 - 6 = 9 feet

Let the angle is θ from the horizontal

By the triangle EBC

tanθ = BC / EB = 9 / 3

tanθ = 3

θ = 71.6°

Thus, the angle from the horizontal is 71.6°.

Explanation:

7 0
4 years ago
The radius RH of a black hole, also known as the event horizon, marks the location where not even light itself can escape from t
olga nikolaevna [1]

Solution:

a) We know acceleration due to gravity, g = GM/r²

Differential change, dg/dr = -2GM/r³

Here, r = 50*Rh = 50*2GM/c² = 100GM/c ²

My height, h=dr = 1.7 m

Difference in gravitational acceleration between my head and my feet, dg = -10 m/s²

or,   dg/dr = -10/1.7 = -2GM/(100GM/c²)³

or,     5.9*100³*G²*M² = 2c⁶

or,   M = 0.59*c³/(1000G) = 2.39*1032 kg = [(2.39*1032)/(1.99*1030 )]Ms = 120*Ms

Mass of black hole which we can tolerate at the given distance is 120 time the mass of Sun.

b) This limit an upper limit ,we can tolerate smaller masses only.

4 0
3 years ago
Think of one example where Bob would need to calculate the net force on a person at the water park.
gregori [183]
Well Bob would need to calculate to net force of someone going down a water slide. Since the person is going down the slide, the person will go faster, depending on their mass/weight and the gravitational pull. As phrased in Newton’s Second Law.


Newton’s Second Law:
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object.
7 0
3 years ago
Which Coefficients balance the following equation? ____Pb(OH)2+_____HCI—&gt; _____ H2O+______PbCl2
lorasvet [3.4K]

the answer is A it is so easy question

3 0
3 years ago
What is the force required to stop a 20 kg man traveling at 12.3 m/s East in 0.9 s? *Round to TWO decimal points and include you
abruzzese [7]

F = ma

We have mass = 20kg

And we need to solve for acceleration

So acceleration is change in velocity over time, in this case we have one velocity and we can assume the man started from rest so

12.3 / 0.9 = a

a = 13.6667

Now we can plug that into F = ma

F = (20)(13.6667)

F = 273.334

Rounding

F = 273.33

Now he is traveling east so we need a force towards the rest, or in the opposite direction to stop his motion.

If we assume east is the positive direction then we need a force of

-273.33 N to stop the man or 273.33 towards the west.

4 0
4 years ago
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