Question

If you can throw a stone straight up to height h, what’s the maximum horizontal distance you could throw it over level ground?

Answer 1

To answer this question, first we take note that the maximum height that can be reached by an object thrown straight up at a certain speed is calculated through the equation,
                            Hmax = v²sin²θ/2g
where v is the velocity, θ is the angle (in this case, 90°) and g is the gravitational constant. Since all are known except for v, we can then solve for v whichi s the initial velocity of the projectile. 

Once we have the value of v, we multiply this by the total time traveled by the projectile to solve for the value of the range (that is the total horizontal distance). 

Answer 2

Answer:

$R = \frac{u^2}{g}$

Explanation:

Maximum distance covered by the stone can be calculated as follows:

$R = \frac{u^2 sin2\theta}{g}$

where, u is the initial velocity, θ is the launch angle and g is the acceleration due to gravity.

For maximum horizontal distance, θ should be 45°. Then maximum distance covered would be:

$R = \frac{u^2}{g}$