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Vlad1618 [11]
3 years ago
6

What happens to a sheet of copper as kinetic energy of copper molecules decrease

Physics
1 answer:
liberstina [14]3 years ago
8 0
First is melts then it expands next it gets cooler Finally it gains ener. Hope this helps you out.
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What is true about the relationship between the kinetic energy of molecules in an object and the objects temperature?
vekshin1

As the temperature increases the kinetic energy of the molecules increases, if u add more heat you get more kinetic energy.

6 0
3 years ago
What is/are the difference between wavelength and spectral lines?
Gre4nikov [31]

Answer:

<u><em>Definition of spectral line: </em></u><em>one of a series of linear images formed by a spectrograph or similar instrument and corresponding to a narrow portion of the spectrum of the radiation emitted or absorbed by a particular source.</em>

<em />

<u><em>Definition of Wavelength:</em></u><em> can be defined as the distance between two successive crests or troughs of a wave. It is measured in the direction of the wave. ... Wavelength is inversely proportional to frequency. This means the longer the wavelength, lower the frequency.</em>

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<em>So, the spectrum is the range of wavelength in visible light. While, wavelength is the length of a wave.</em>

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Explanation:

I hope this helps!

8 0
2 years ago
What is electropower​
OLEGan [10]

Answer:

electricity

Explanation:

8 0
3 years ago
Read 2 more answers
A skater has rotational inertia 4.2 kg.m2 with his fists held to his chest and 5.7 kg.m2 with his arms outstretched. The skater
Fynjy0 [20]

Answer:

6.13428 rev/s

Explanation:

I_f = Final moment of inertia = 4.2 kgm²

I = Moment of inertia with fists close to chest = 5.7 kgm²

\omega_i = Initial angular speed = 3 rev/s

\omega_f = Final angular speed

r = Radius = 76 cm

m = Mass = 2.5 kg

Moment of inertia of the skater is given by

I_i=I+2mr^2

In this system the angular momentum is conserved

L_f=L_i\\\Rightarrow I_f\omega_f=I_i\omega_i\\\Rightarrow \omega_f=\dfrac{I_i\omega_i}{I_f}\\\Rightarrow \omega_f=\dfrac{(5.7+2\times 2.5\times 0.76^2)3}{4.2}\\\Rightarrow \omega_f=6.13428\ rev/s

The rotational speed will be 6.13428 rev/s

5 0
2 years ago
An object rotates about a fixed axis, and the angular position of a reference line on the object is given by θ = 0.220e3t, where
OLga [1]

Answer:a_{t}=3.96

a_{c}=0.8712

Explanation:

Given

\theta =0.220e^{3t}

r=2cm

Now angular velocity is given by \omega =\frac{\mathrm{d}\theta}{\mathrm{d}t}

\omega =0.66e^{3t}

Now linear velocity(v) is given =\omega r

v=1.32e^{3t}

Now tangential component of acceleration is given by

a_{t}=\frac{\mathrm{d}\vec{v}}{\mathrm{d}t}=3.96e^{3t}

at t=0

a_{t}=3.96cm/s^2

radial component of acceleration is given by

a_{c}=\omega ^{2}r

a_{c}=0.4356e^{6t}\times 2

a_{c}=0.8712e^{6t} cm/s^{2}

at t=0

a_c=0.8712 cm/s^{2}

5 0
3 years ago
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