To solve this problem we will begin by finding the pressure through density and average depth. Later we will find the Force, by means of the relation of the pressure and the area.

Here,
h = Depth average
= Density
Moreover,

Replacing,


Finally the force



Answer:
v = 0.489 m/s
Explanation:
It is given that,
Mass of a box, m = 1.5 kg
The compression in the spring, x = 6.5 cm = 0.065 m
Let the spring constant of the spring is 85 N/m
We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.


So, the speed of the box is 0.489 m/s.
Answer:
4.186 m/s^2
Explanation:
First, convert km/hr to m/s:
(75 km/hr)(1000m/1km)(1hr/60min)(1min/60s) = 20.83 m/s
Then, divide 20.93 m/s by 5.0s
(20.93 m/s) / (5.0s) = 4.186 m/s^2