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jarptica [38.1K]
3 years ago
6

How does Water Pollution effect the economy

Physics
1 answer:
Lelechka [254]3 years ago
5 0
Water pollution can affect the economy because with no clean water, people will be forced to buy water bottles impacting their disposable income. In the search for clean water, potential future conflicts may occur because water is a fundamental need to human survival. :) 
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What is the acceleration due to gravity of an object with a mass of 10000 g?
Aleks [24]

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

<h3>What is gravitational constant?</h3>

According to Sir Isaac Newton's rule of universal gravitation and Albert Einstein's theory of general relativity, the gravitational constant, indicated by the capital G, is an empirical physical constant that is used to calculate the gravitational effects.

<h3>According to the given information:</h3>

mass of object = 10kg

gravitational constant = 6.67 x 10^-11

radius of earth  = 6.3 x 10^6

we know that:

acceleration due to gravity = GM/R²

                                             = ((6.67 x 10^-11)*10)/(6.3 x 10)²

Solving this we get :

42.02 x 10^-16 m/s²

The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²

To know more about acceleration due to gravity visit:

brainly.com/question/13860566

#SPJ4

7 0
1 year ago
A 2,000kg car uses a braking force of 12,000 N to stop in 5 s
I am Lyosha [343]

Knowing the amount of force F and the length of time t that force is applied to an object will tell you the resulting change in its momentum ΔP . This is:

F*t = ΔP

ΔP = F*t    <em>but ΔP = mv</em>

mv = F*t

v = F*t/m

v = 12000 N × 5 s / 2000 kg

<h3>v = 30 m/s</h3><h2 /><h2>A/ The initial speed of the car was 30 m/s</h2>
5 0
3 years ago
I dont know what it is so help me im depending you on this one with my grades
tigry1 [53]
“Newton's first law says that the tableware will remain motionless unless acted upon by an outside force. To set the objects on the table into motion, the horizontal force acting upon them in this case is the frictional force between them and the table cloth. “

couldn’t paraphrase i’m not too good at physics but this might help
3 0
3 years ago
3. A car travels 800 miles in 6 hours. What was the car’s average speed? Be sure to include units in your answer
vredina [299]

Answer:

133.33 miles per hour

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained.

5 0
2 years ago
You have a stopped pipe of adjustable length close to a taut 85.0cm, 7.25g wire under a tension of 4170N. You want to adjust the
Makovka662 [10]

Answer:

The length is L_d= 0.069 \ m

Explanation:

From the question we are told that

               The length of the wire  L = 85cm = \frac{85}{100}  = 0.85m

                The mass is  m = 7.25g = \frac{7.25}{1000}  = 7.25^10^{-3}kg

                The tension is  T = 4170N

Generally the frequency of  oscillation of a stretched wire is mathematically represented as

             f = \frac{n}{2L} \sqrt{\frac{T}{\mu}

Where n is the the number of nodes = 3 (i.e the third harmonic)

             \mu is the linear mass density of the wire

 This linear mass density is mathematically represented as

               \mu = \frac{m}{L}

Substituting values

            \mu = \frac{7.2*10^{-3}}{0.85}

                = 8.53 *10^{-3} kg/m

 Substituting values in to the equation for frequency

            f = \frac{3}{2 80.85} * \sqrt{\frac{4170}{8.53*10^{-3}} }

               = 1234Hz

From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire

The fundamental frequency is mathematically represented as

        f = \frac{v}{4L_d}

Where L_d is the  length of the pipe

          v is the speed of sound with a value of v = 343m/s

    Making  L_d the subject of the formula

                      L_d = \frac{v}{4f}

   Substituting values

                   L_d = \frac{343}{(4)(1234)}

                        L_d= 0.069 \ m

From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire

6 0
2 years ago
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