The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²
<h3>What is gravitational constant?</h3>
According to Sir Isaac Newton's rule of universal gravitation and Albert Einstein's theory of general relativity, the gravitational constant, indicated by the capital G, is an empirical physical constant that is used to calculate the gravitational effects.
<h3>According to the given information:</h3>
mass of object = 10kg
gravitational constant = 6.67 x 10^-11
radius of earth = 6.3 x 10^6
we know that:
acceleration due to gravity = GM/R²
= ((6.67 x 10^-11)*10)/(6.3 x 10)²
Solving this we get :
42.02 x 10^-16 m/s²
The acceleration due to gravity of an object with a mass of 10000 g = 42.02 x 10^-16 m/s²
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Knowing the amount of force F and the length of time t that force is applied to an object will tell you the resulting change in its momentum ΔP . This is:
F*t = ΔP
ΔP = F*t <em>but ΔP = mv</em>
mv = F*t
v = F*t/m
v = 12000 N × 5 s / 2000 kg
<h3>v = 30 m/s</h3><h2 /><h2>A/ The initial speed of the car was 30 m/s</h2>
“Newton's first law says that the tableware will remain motionless unless acted upon by an outside force. To set the objects on the table into motion, the horizontal force acting upon them in this case is the frictional force between them and the table cloth. “
couldn’t paraphrase i’m not too good at physics but this might help
Answer:
133.33 miles per hour
Explanation:
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So there are a wats up group where you can get help step by step and well explained.
Answer:
The length is 
Explanation:
From the question we are told that
The length of the wire 
The mass is 
The tension is 
Generally the frequency of oscillation of a stretched wire is mathematically represented as

Where n is the the number of nodes = 3 (i.e the third harmonic)
is the linear mass density of the wire
This linear mass density is mathematically represented as
Substituting values


Substituting values in to the equation for frequency


From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire
The fundamental frequency is mathematically represented as

Where
is the length of the pipe
v is the speed of sound with a value of 
Making
the subject of the formula
Substituting values


From the question the we can deduce that the fundamental frequency is equal to the oscillation of a stretched wire