We dont see objects. We see the light ___

If a voltmeter has a less than ideal resistance, say 1 MΩ, and is used to measure the voltage across a resistor of a comparable

Naddik [55]

Answer:

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased.

Explanation:

An ideal voltmeter has infinite parallel resistance and because of this it doesn't draw any current from the circuit of measurement which means it will measure the exact voltage across the elements.

But practically speaking, a real voltmeter doesn't has infinite resistance therefore, all the practical voltmeters face loading effect to some extent.

As the difference between the resistance of voltmeter and the resistance being measured gets reduced the error in the reading of the voltmeter gets increased. This is why we want to have a greater value of voltmeter resistance, ideally infinite so that the corresponding error is minimized.

Lets consider the given scenario,

A voltmeter has 1 MΩ parallel resistance and the resistance of of measuring element is 500 kΩ or 0.5 MΩ

lets suppose the supplied voltage is 1 V.

First lets assume that the voltmeter is ideal and it has infinite resistance, so in this case voltmeter will measure a voltage of 1 V across the 0.5 MΩ resistor.

Now consider the loading effect, when we connect the voltmeter across the 0.5 MΩ resistor they both become parallel so the resistance is

R = (1*0.5)/(1+0.5)

R = 0.33 MΩ

As you can see the voltmeter will see a reduced resistance and the corresponding voltage also reduces because resistance and voltage are directly proportional.

Therefore, it is preferred to have a very high parallel resistance of the voltmeter.

8 0

3 years ago

A student has made the statement that the electric flux through one half of a Gaussian surface is always equal and opposite to t

nata0808 [166]

Answer:

E.true only when no charge is enclosed within the Gaussian surface.

Explanation:

Because Gauss’s law states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.

6 0

3 years ago

A stone is thrown downward with a speed of 8 m/s from a height of 14 m. (acceleration due to gravity: 10 m/s2) What is the speed

max2010maxim [7]

Answer:

The speed of the stone just before it hits the ground is 18.54 m/s

Explanation:

Given that,

Initial speed of the stone, u = 8 m/s

The stone is thrown downward from a height of 14 m

We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :

$v^2-u^2=2ah$

v is the speed of the stone just before it hits the ground

$v^2=2ah+u^2$

$v^2=2\times 10\times 14+(8)^2$

v = 18.54 m/s

So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.

6 0

3 years ago

If the axes of the two cylinders are parallel, but displaced from each other by a distance d, determine the resulting electric f

Novay_Z [31]

Answer:

E = ρ ( R1²) / 2 ∈o R

Explanation:

Given data

two cylinders are parallel

distance = d

radial distance = R

d < (R2−R1)

to find out

Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants

solution

we have two parallel cylinders

so area is 2 $\pi$ R × l

and we apply here gauss law that is

EA = Q(enclosed) / ∈o ......1

so first we find Q(enclosed) = ρ Volume

Q(enclosed) = ρ ( $\pi$ R1² × l )

so put all value in equation 1

we get

EA = Q(enclosed) / ∈o

E(2 $\pi$ R × l) = ρ ( $\pi$ R1² × l ) / ∈o

so

E = ρ ( R1²) / 2 ∈o R

6 0

3 years ago

Assume this car is driven off a cliff. How many arrows of force need to be drawn in the free body diagram? Assum no air resistan

kirza4 [7]

Answer:

4

Explanation:

friction

weight

normal reaction

force to overcome inertia

4 0

3 years ago

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We dont see objects. We see the light ____ off objects.