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ivann1987 [24]
3 years ago
11

State the pressure law

Physics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0
The pressure law states: "For a fixed mass of gas, at a constant volume, thepressure<span> (p) is directly proportional to the absolute temperature (T)."</span>
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A car moves from rest condition moves with acceleration 4 ms^-2.After 5s,calculate velocity of the car and the distance traveled
lisov135 [29]

Answer:

1) 20 m/s

2) 60 meters

Explanation:

with a constant acceleration of 4m/s/s, the vehicle will end up traveling at 20 m/s after 5 seconds, and will have travelled 60 meters.

5 0
4 years ago
You have an unpolarized light source and you wish to send a beam of this light with intensity Io through a number of sheets of p
tekilochka [14]

Answer:

Explanation:

a ) The angle  between the polarization axis of two adjecent sheet

= 90 / 3 = 30 degree.

The formula for intensity of polarised light from unpolarised light ( first transmission

I₁ = I₀ /2

I₀ is intensity of unpolarised light and I₁ is intensity of light after first time polarization .

The relation of I₁ and I₂ is as follows

I₂ = I₁ cos²30

= I₀/2 x3/4

=3 I₀/8

Relation between I₃ and I₂ is as follows

I₃ = I₂ cos²30

= 3I₀ / 8 x 3/4

= 9 I₀ / 32

= 0 .28 I₀

In case of stack of 4 plates

angle between two plates  = 90/4  = 22.5 degree

I₁ = I₀ /2

I₂ = I₁ cos²22.5

=  I₀ /2 x .85

I₃ = I₂ cos²22.5

= I₀ /2 x .85 x .85

= .36 I₀

7 0
3 years ago
Need help on this please
Likurg_2 [28]
Build up of pressure between tectonic plates .
8 0
3 years ago
A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the
ololo11 [35]

Answer:

7.3 newtons to the west

Explanation:

3.7kg × 11a - 3.7kg × ? = 3.7n

4 0
3 years ago
A car is traveling at 52.4 km/h on a flat
natali 33 [55]
Work is equal to a force over a distance and is equal to the change in kinetic energy, so
<span>
- Fd=ΔKE
</span> <span>−Fd=1/2m<span>v22</span>−1/2m<span>v21</span></span>
<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−F

</span> We know that Ffric=kFnatural and Fnatural=mg so:

<span>d=(1/2m<span>v22</span>−1/2m<span>v21</span>)/−(k∗mg)</span><span>d=(−1/2<span>v21</span>)/−(k∗g)

</span><span>d=(−1/2×(14.6m/s<span>)2</span>)/−(0.137×9.8m/s)

</span><span> d = 78.9m</span>
8 0
3 years ago
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