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3 years ago

Which combination of reactants would result in a neutralization reaction with sodium nitrate,

Chemistry

1 answer:

Debora [2.8K]3 years ago

7 0

Answer:

(B) HNO3 + NaOH

Explanation:

Hello,

In this case, for the production of sodium nitrate a substance having the sodium as a cation should react with another substance having the nitrate anion. Moreover, neutralization reactions are carried out when bases react with acids, such is the case of nitric acid and sodium hydroxide:

$NaOH+HNO_3\rightarrow NaNO_3+H_2O$

Thus, the answer is (B) HNO3 + NaOH as the other options involve salts rather than acids or bases as starting reactants.

Regards.

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tamaranim1 [39]

Answer: increase

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1 year ago

Conductors have(blank) resistance. Moderate. Very High. Very low.

Flura [38]

Answer:

The correct option is C) Very low

Explanation:

In physics, resistance can be described as the opposition to the flow of current or the flow of electrons. Conductors are known to be materials which can conduct electricity. Hence, conductivity and resistance are opposite to each other. Good conductors will have very little or no resistance and will have enhanced conductivity. On the contrary, insulators are materials which will have more resistance and they cannot conduct electricity as efficiently.

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3 years ago

Consider the titration of 82.0 mL of 0.140 M Ba(OH)2 by 0.560 M HCl. Calculate the pH of the resulting solution after the follow

oksano4ka [1.4K]

Answer:

a) pH = 13.447

b) pH = 13.176

Explanation:

Ba (OH)₂ is a strong base and ionizes completely in solution to give barium amend hydroxide ions.

The equation of the dissociation of Ba(OH)₂ is given below:

Ba(OH)₂ ----> Ba2+ + 2OH-

1 mole of Ba(OH)₂ produces 2 Moles of OH- ions

a) Before the addition of HCl, i.e.,when 0.00 mL of HCl has been added;

Concentration of hydroxide ions, [OH-] = 0.140 x 2 = 0.a) [OH-] = 0.100 x 2 = 0.280

pOH = -log [OH-]

pOH = -log (0.280)

pOH = 0.553

pH = 14 - 0.553= 13.447

b) pH when 15.0 mL HCl has been added

Moles Ba(OH)₂ = concentration × volume

Volume of Ba(OH)₂ = 82.0 mL = 0.082 L, concentration = 0.140 M

moles of Ba(OH)₂ = 0.082 x 0.140 = 0.01148 moles

moles OH- produced by 0.01148 moles of Ba(OH)₂ = 2 x 0.01148= 0.02296

moles HCl = 0.0150 L x 0.560 = 0.0084

moles of H+ produced by 0.0084 HCl = 0.0084

0.0084 H+ willnreact with 0.0084 moles of OH-

moles OH- left after the reaction = 0.02296 - 0.0084 = 0.01456 moles

total volume of new solution = (82 +15) mL = 97 mL => 0.097 L

Concentration of OH- ions = moles / volume

[OH-] = 0.01456 / 0.097 = 0.1501

pOH = -log [OH-]

pOH = -log (0.150)

pOH = 0.824

pH = 14 - 0.824

pH = 13.176

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2 years ago

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Answer:

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