D. HCIO4(AQ)
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Answer:
Ag⁺(aq) + Cl⁻(aq) → AgCl(s)
Explanation:
The silver nitrate, AgNO₃, dissolves in water as follows:
AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)
The Ag⁺ reacts with Cl⁻ producing AgCl(s), a white insoluble salt. The net ionic equation that describes the formation of the precipitate is:
<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 /><h3 />
Answer:
0.73 mol
Explanation:
No. of moles(n)= Given mass/molar mass.
Given mass=124.7g
Molar mass of Ba(OH)2= Molar mass of (Barium+2Oxygen+2Hydrogen)=137+32+2=171g
No. of moles= 124.7g/171g=0.73 mol
Answer:
Your question is missing some information.
But in most of the systems, potential energy and kinetic energy are inversely proportional
Answer:
69.7% is percent yield
Explanation:
Based on the reaction:
3Ca(NO3)2(aq) + 2Na3PO4(aq) → Ca3(PO4)2(s) + 6NaNO3(aq)
2 moles of Na3PO4 react producing 6 moles of NaNO3.
As 24.2 moles of Na3PO4 react, theoretical moles of NaNO3 produced are:
24.2 moles Na3PO4 * (6 moles NaNO3 / 2 moles Na3PO4) =
72.6 moles of NaNO3
As there are produced 50.6 moles of NaNO3, percent yield is:
50.6 moles NaNO3 / 72.6 moles NaNO3 =
<h3>69.7% is percent yield</h3>