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katrin [286]
3 years ago
12

train travel from hong kong to beijing it traveled at an average speed of 160 km/m in the first 4 hours. after that it traveled

another average speed of 180 km/m. if the distance between hong kong to bejing is 1180 km, what was the total time for the whole journey?
Chemistry
2 answers:
Nonamiya [84]3 years ago
5 0

Answer:

7 hours

Explanation: step 1. 160x4=640

step 2. 1180-640=540

step 3. 540÷180=3

step 4. 3+4=7

Scrat [10]3 years ago
5 0

Answer:

7 hours

Explanation:

Speed of train in first 4 hours = 160 km/h

Speed of train after 4 hours = 180 km/h

Distance = Speed × Time

Distance=160\times 4=640\ km

Distance traveled in first 4 hours = 640 km

Distance remaining = 1180-640 = 540 km

Time = Distance / Speed

Time=\frac{540}{180}=3\ hours

Total time taken by the train is 4+3 = 7 hours

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A doctor's Order is 0.125 g of ampicillin. The liquid suspension on hand contains 250 mg/s. How many milliliters (mL) of the sus
Molodets [167]

Answer:

c) 2.5 mL

Explanation:

Solution

Doctors order = 0.125g

and

The liquid suspension concentration = 250 mg/5ml

= 0.250g/5ml

Or 0.05g/ml

Amount of ml of suspension required = 0.125g/(0.05g/ml) = 2.5ml

7 0
3 years ago
Someone help me please ​
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5 0
2 years ago
1. Which sample contains a total of 9.0 * 10 ^ 23 atoms ? A) 0.50 mole of HCI B) 0.75 mole of H 2 O C) 1.5 moles of Cu D) 1.5 mo
Alchen [17]

c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.

Explanation:

To convert moles into atoms,  the molar amount and number of atom is multiplied by Avagadro's number.

Avagadro's number is 6.022×10^{23}  

So applying the formula in the given sample:

A) 0.5×6.022×10^{23}

   3.01×10^{23} atoms.

B) 0.75 mole of H20

O.75×6.022×10^{23}

= 4.5166×10^{23}  atoms.

C) 1.5 moles of Cu

  1.5×6.022×10^{23}

  =  9.033×10^{23}

D). 1.5 moles of H2

1.5 × 2 × 6.022 × 10^{23}

= 18.066 × 10^{23} atoms   because H2 is 2 moles of hydrogen.

Atom is the smallest entity of matter having property of the element to which it is a part.

8 0
2 years ago
Determine whether a precipitate will form when 0.96g of Na2CO3 is combined with 0.20g BaBr2 in a 10 L solution.
Mashcka [7]

Answer:

Qsp > Ksp, BaCO3 will precipitate

Explanation:

The equation of the reaction is;

Na2CO3 + BaBr2 -------> 2NaBr + BaCO3

Since BaCO3 may form a precipitate we can determine the Qsp of the system.

Number of moles of Na2CO3 = 0.96g/106 g/mol = 9.1 * 10^-3 moles

concentration of NaCO3 = number of moles/volume of solution = 9.1 * 10^-3 moles/10 L = 9.1 * 10^-4 M

Number of moles of BaBr2 = 0.20g/297 g/mol = 6.7 * 10^-4 moles

concentration of BaBr2 = 6.7 * 10^-4 moles/10 L = 6.7 * 10^-5 M

Hence;

[Ba^2+] = 6.7 * 10^-5 M

[CO3^2-] = 9.1 * 10^-4 M

Qsp = [6.7 * 10^-5] [9.1 * 10^-4]

Qsp = 6.1 * 10^-8

But, Ksp for BaCO3 is 5.1*10^-9.

Since Qsp > Ksp, BaCO3 will precipitate

3 0
3 years ago
1.505 times 10^23 Na atoms
dybincka [34]

5.75g

Explanation:

Given parameters:

Number of atoms = 1.505 x 10²³atoms

let us find the number of moles and mass of this atom.

Solution:

The mole is convenient unit for reporting measurements in chemistry. It allows us to make mathematical calculations:

     one mole of substance contains 6.02 x 10²³atoms

Number of moles of Na given = \frac{1.505 x 10^{23} }{6.02 x 10^{23} }  = 0.25moles

Mass of Na atom given = number of moles x molar mass

   Molar mass of Na= 23g/mole

Mass of Na = 0.25 x 23 = 5.75g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

8 0
3 years ago
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