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Illusion [34]
2 years ago
8

What volume does 49g of KBr need to be dissolved in to make a 8.48% (w/v) solution?

Chemistry
1 answer:
dybincka [34]2 years ago
5 0

Answer:

Volume of solution = 577.83 ml (Approx)

Explanation:

Given:

% of (W/V) = 8.48%

Weight of KBr in gram = 49 gram

Find:

Volume of solution

Computation:

% of (W/V) = Weight of KBr in gram / Volume of solution

8.48% = 48 / Volume of solution

Volume of solution = 49 / 8.48%

Volume of solution = 577.83 ml (Approx)

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A chemist adds 0.50L of a 0.485 M copper(II) sulfate CuSO4 solution to a reaction flask. Calculate the millimoles of copper(II)
den301095 [7]

Explanation:

It is given that volume is 0.50 L and molarity is 0.485 M. Hence, number of millimoles will be calculated as follows.

               Number of millimoles = Molarity × Volume

As there are 1000 mL in 1 L. So, 0.50 L equals 500 mL.

Therefore, putting the given values into the above formula as follows.

             Number of millimoles = Molarity × Volume

                                                 = 0.485 M × 500 mL      

                                                 = 242.5

Thus, we can conclude that 242.5 millimoles of copper(II) sulfate has been added by the chemist to the flask.                                      

4 0
3 years ago
Temperature in degrees Fahrenheit can be converted to Celsius by first subtracting 32, then dividing by 1.8. What is the Celsius
kap26 [50]

Answer:

31.1°C

Explanation:

Given parameters:

  Temperature = 88°F

The formula of the to convert is:

         T°F = T°C - 32  / 1.8  = \frac{TC - 32}{1.8}

Now input the parameters and solve;

       T°F =\frac{ 88  -32}{1.8}

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7 0
2 years ago
Read 2 more answers
QUESTION 1
Svetlanka [38]

Answer:

C

Explanation:

Because nothing is left at the end of the reaction.

3 0
2 years ago
The nearest whole number of 99.59
Anna [14]
It is 100 because a 5 and up means you round up. also the 9 makes it a 6 rounded up
7 0
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Consider this hydrocarbon. A hexagon. Is this an aromatic hydrocarbon? Why or why not? Yes, because the carbon chain is made up
grin007 [14]

Answer:

C. No, because the carbon chain is composed of only a single ring.

Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

Explanation:

Cyclic Hydrocarbons

These are organic compounds which are cyclic in structure. The compound cyclohexane involves a ring of six carbon atoms, each of which is also bonded to two hydrogen atoms

Aromatic hydrocarbons are cyclic ring organic compound which are based on the benzene ring structure.

A. If the hexagon contains single bonds, it is non-aromatic.

B. No. Having a ring shape does not on its own determine the aromaticity of a hydrocarbon.

C. Polycyclicity, having more than a single ring, is a property of only aromatic hydrocarbons. Therefore, if the hydrocarbon is not polycyclic, it is non-aromatic

D. Having double bonds within a ring is not a criteria for being aromatic. Both aromatic and non-aromatic hydrocarbons have double bonds within their rings. However, aromatic hydrocarbons have alternate double and single bonds within their 6-carbon ring structure.

Note: Since the structure of the required hydrocarbon is not shown, the explanation contains attachments of hexagonal structures of three hydrocarbons; one non-aromatic and the other two are aromatic. Cyclohexane is non-aromatic while Benzene and the polycyclic compounds are aromatic.

7 0
3 years ago
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