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faust18 [17]
4 years ago
13

What happens to potential energy that is not completely converted to kinetic

Physics
1 answer:
Arada [10]4 years ago
7 0

Answer:

There is a possibility that it will be converted to another form, but based on the context the answer is A. It is stored as potential energy.

Explanation:

This is because potential energy means that the energy has the <u>potential</u> to release energy to do work, but it has not yet. So if it has not been transferred to anything, and the object has already had the ability to have potential energy, then it will stay as potential until released.

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A boat is able to move through still water at 20 m/s. It makes a round trip to a town 3.0 km upstream. If the river flows at 5m/
Salsk061 [2.6K]

Answer:

Option e) 320 s

Explanation:

Here, distance = 3.0 km = 3000 m

The velocity of boat when it is going upstream;

Upstream velocity = velocity of boat in still water - velocity of river flow

So, Upstream velocity =20m/s-5m/s=15m/s

So,Time to go upstream

(t_{1}) =\frac{Distance}{Velocity}=\frac{3000m}{15m/s} =200 s

The velocity of boat when it is going downstream;

Downstream velocity = velocity of boat in still water + velocity of river flow

So, Downstream velocity =20m/s+5m/s=25m/s

So,Time to go downstream

(t_{2}) =\frac{Distance}{Velocity}=\frac{3000m}{25m/s} =120 s

So, total time (t) = t_{1}+t_{2}=200s+120 s=320s

Option E is the correct answer.

3 0
4 years ago
Read 2 more answers
Two very small spheres are initially neutral and separated by a distance of 0.30 m. Suppose that 2.50 1013 electrons are removed
quester [9]

Answer:

F = - 1,598 10⁻³ N

Explanation:

Electic strength is given by Coulomb's law

          F = k q₁ q₂  / r²

Where k is the Coulomb constant that is worth 8.99 10⁸ N m²/C², q₁ and q₂ are the charges and r is the distance that separates the electric charges

In this case the charge of the two spheres is the same and of a different sign since when you remove the charge of a sphere that was initially neutral, it is left with that charge removed but of the opposite sign

       q₁ = q₂ = 2.50 10¹³ electrons = 2.50 10¹³ 1.6 10⁻¹⁹

       q₀ = 4.0 10⁻⁶ C

Let's calculate

       F = - 8.99 10⁸ (4.0 10⁻⁶)² / 0.30²

       F = - 1,598 10⁻³ N

4 0
4 years ago
A solid disk of radius 5.50 cm and mass 1.25 kg , which is rolling at a speed of 1.50 m/s , begins rolling without slipping up a
shtirl [24]

Answer:

Explanation:

Deceleration of solid disk = g sin10/1 + k²/r² = g sin 10 / 1 + 1/2 = g sin 10 x 2/3

[ k is radius of gyration of disk which is equal to( 1/√2)x r ]

deceleration a = -1.1345 m/s²

v = u - at , t = u / a = 1.5 / 1.1345 = 1.322 s.

5 0
3 years ago
A 330-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,110 A. If the conductor is copper
vodka [1.7K]

Answer:

t = 402 years

Explanation:

To find the number of year that electrons take in crossing the complete transmission line, you first calculate the drift speed of the electrons. Then, you use the following formula for the current in a wire:

I=nqv_dA  (1)

n: number of mobile charge carrier per volume = 8.50*10^28 e/m^3

q: charge of the electron = 1.6*10^-19 C

vd: drift velocity of electron in the metal = ?

A: cross sectional area of the wire = π r^2 = π (0.02m/2)^2 = 3.1415*10^-4 m^2

I: current in the wire = 1110 A

You solve the equation (1) for vd:

v_d=\frac{I}{nqA}=\frac{110A}{(8.50*10^{28}m^{-3})(1.6*10^{-19}C)(3.1415*10^{-4}m^2)}\\\\v_d=2.59*10^{-4}m/s

Next, you calculate the time by using the information about the length of the line transmission:

x=v_dt\\\\x=330km=330000m\\\\t=\frac{x}{v_d}=\frac{330000m}{2.59*10^{-4}m/s}=1,270,184,865s\\\\1,270,184,865s*\frac{1\ year}{3,156,107}=402.45\ years

hence, the electrons will take aproximately 402 years in crossing the line of transmission

6 0
4 years ago
The vibrations of a string fixed at both ends are represented by y=16sin(πx/15 )cos(96πt). Where x and y are in cm and t in seco
patriot [66]

Answer:

Explanation:

y = 16 sinπx/15 cos(96πt)

When t = 0

y = 16 sinπx/15

here πx/15 is phase of the point at x

if x = 13

Phase = 13π/15

if x = 16

Phase = 16π/15

Phase difference

= 16π/15 - 13π/15

= 3π/15

= π/5 radian .

7 0
4 years ago
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