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gavmur [86]
3 years ago
9

While Calvin is doing a physics experiment outside with a radar gun, he notices that after three seconds a car reaches a speed o

f 20 m/s while accelerating at 3 m/s squared. what was the initial velocity of the car?
Physics
1 answer:
nirvana33 [79]3 years ago
3 0

The initial velocity of the car is 11 m/s.

Explanation:

  • Here, we can use the equations of motions.
  • The first of equation of motion is v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
  • The given parameters are,

Final velocity, v = 20 m/s

acceleration of the care, a = 2 m/s^{2}

time, t = 3 s

Initial velocity, u = ?

  • Hence, the equation can be written as u = v - at

once you substitute all these vales, you will get u = 11 m/s

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Two wires with the same resistance have the same diameter but different lengths. If wire 1 has length L 1 and wire 2 has length
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Answer with Explanation:

We are given that

Length of wire 1=L_1

Length of wire 2=L_2

Resistivity of copper wire=\rho_1=1.7\times 10^{-5}\Omega-m

Resistivity of aluminum wire=\rho_2=2.82\times 10^{-5}\Omega-m

Wire 1=Copper wire

Wire 2=Aluminum wire

Diameter of both wires are same and resistance of both wires are also same.

We know that

Resistance =\frac{\rho l}{A}

When diameter of wires are same then their cross section area are also same .

l=\frac{RA}{\rho}

When resistance and area are same then the length of wire depend upon the resistivity of wire .

The length of wire is inversely proportional to resistivity.

When resistivity is greater then the length of wire will be short and when the resistivity  is small then the length of wire will be large.

\rho_1

Therefore, L_1>L_2

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L_1=1.66L_2

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