To solve this problem we will apply the concepts related to the Doppler effect. The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. Mathematically it can be described as

The meaning of each of these variables is,
Velocity of detector
=Frequency of wave emitted by source
Velocity of source
v=Velocity of sound wave
=Frequency received by detector
Replacing we have that,


Therefore the correct option is e. 950Hz
Answer:
0.68 kg-m²
Explanation:
F = Force applied by the muscle = 2615 N
r = effective perpendicular lever arm = 2.85 cm = 0.0285 m
α = Angular acceleration of the forearm = 110.0 rad/s²
I = moment of inertia of the boxer's forearm = ?
Torque is given as
τ = I α eq-1
Torque is also given as
τ = r F eq-2
using eq-1 and eq-2
r F = I α
(0.0285)(2615) = (110.0) I
I = 0.68 kg-m²
Helped us in modern days do to his contribution to the study of motion back in the day is what helpes us know how to study motion.
The kinetic energy is greater on the second hill
hope i helped have a great day
The voltage across an inductor ' L ' is
V = L · dI/dt .
I(t) = I(max) sin(ωt)
dI/dt = I(max) ω cos(ωt)
V = L · ω · I(max) cos(ωt)
L = 1.34 x 10⁻² H
ω = 2π · 60 = 377 /sec
I(max) = 4.80 A
V = L · ω · I(max) cos(ωt)
V = (1.34 x 10⁻² H) · (377 / sec) · (4.8 A) · cos(377 t)
<em>V = 24.25 cos(377 t)</em>
V is an AC voltage with peak value of 24.25 volts and frequency = 60 Hz.