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Alchen [17]
3 years ago
6

A squirrel, named jumping Jacky rides on a remote-controlled toy car in a circle in the horizontal x-y plane of radius of 45.0 m

. If the car is travelling with a constant tangential velocity of 36.0 m/s, what is the magnitude of the centripetal acceleration vector and its direction (does it point toward or away from the center of the circle or along the path that Jackie takes)?
Physics
1 answer:
viktelen [127]3 years ago
8 0

Answer:  28.8 m/sec², towards the center of the circle.

Explanation:

By definition, acceleration is defined as the quotient between a change in velocity (in value or direction) over time.

In this case, even the velocity value is constant, is changing direction all the time, so there is an acceleration present.

This acceleration is called the centripetal acceleration, and always aims to the center of the circle, because otherwise the toy car will move in a straight line at constant speed, like is dictated by Newton's First law.

It can be showed that it can be calculated as follows:

a = V² /  R  =  (36.0)² (m/s)² /  45.0 m = 28.8 m/s, pointing towards the center of the circle.

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C. mediates communication from the brain to the rest of the body

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4 years ago
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Explain How people can achieve an environmentally sustainable society .
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6 0
4 years ago
g Two long parallel wires are a center-to-center distance of 2.50 cm apart and carry equal anti-parallel currents of 2.70 A. Fin
schepotkina [342]

Answer:

864 mT

Explanation:

The magnetic field due to a long straight wire B = μ₀i/2πR where μ₀ = permeability of free space = 4π × 10⁻⁷ H/m, i = current in wire, and R = distance from center of wire to point of magnetic field.

The magnitude of magnetic field due to the first wire carrying current i = 2.70 A at distance R which is mid-point between the wires is B = μ₀i/2πR.

Since the other wire also carries the same current at distance R, the magnitude of the magnetic field is B = μ₀i/2πR.

The resultant magnetic field at B is B' = B + B = 2B = 2(μ₀i/2πR) = μ₀i/πR

Now R = 2.50 cm/2 = 1.25 cm = 1.25 × 10⁻² m and i = 2.70 A.

Substituting these into B' = μ₀i/πR, we have

B' = 4π × 10⁻⁷ H/m × 2.70 A/π(1.25 × 10⁻² m)

B = 10.8/1.25 × 10⁻⁵ T

B = 8.64 × 10⁻⁵ T

B = 864 × 10⁻³ T

B = 864 mT

4 0
3 years ago
What is the mass of an object traveling at 20 m/s with a kinetic energy of 4000 J?<br>​
valentinak56 [21]

Answer:

20 kg

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Kinetic energy=½*Mass * velocity²

4000= ½* m*20²

8000=400m

m=8000/400

m=20 kg

5 0
3 years ago
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