at t=T/6, total distance covered= 2*pi*r/6 and displacement= r
difference of them = 2*t
so, 2*pi*r/6- r =2(1/6)=1/3
r=1/(pi-3)=7.062
Work done=mgh
W=force*height
W=5N*0.50mts
W=2.5joule
Answer:
The answer is temperature lol
Explanation:
:)
Answer:
school, relashonships, etc.
Explanation: