30 km/h * 17 h = 30*17 km/h *h
= 510 km
Let and be the vectors, and let be their common magnitude.
The resultant is times larger in magnitude than either vector alone, so .
Recall the dot product identity
where is the angle between the vectors and . In the special case of , we get
Now, to get the angle between and , we have
To compute the dot product, we take the dot product of the resultant with itself.
Solve for .
Since their dot product is zero, and are perpendicular, so .
Answer:
11.4 m
Explanation:
We are given that
Total distance traveled by cab,d=214 m
Maximum speed of cab=v=315 m/min=
1 min =60 s
Acceleration of cab=
We have to find the distance traveled by the cab while accelerating to full speed from rest.
Initial speed o f cab=u=0
Substitute the values in the formula
Hence, the cab travel 11.4 m from rest to full speed.
<h2>
Answer:</h2><h3>
<em><u>Alexander Graham Bell</u></em></h3><h2>
Explanation:</h2>
Alexander Graham Bell is often credited as the inventor of the telephone since he was awarded the first successful patent.
Answer:
Explanation:
For this interesting problem, we use the definition of centripetal acceleration
a = v² / r
angular and linear velocity are related
v = w r
we substitute
a = w² r
the rectangular body rotates at an angular velocity w
We locate the points, unfortunately the diagram is not shown. In this case we have the axis of rotation in a corner, called O, in one of the adjacent corners we call it A and the opposite corner A
the distance OB = L₂
the distance AB = L₁
the sides of the rectangle
It is indicated that the acceleration in in A and B are related
we substitute the value of the acceleration
w² r_A = n r_B
the distance from the each corner is
r_B = L₂
r_A =
we substitute
\sqrt{L_1^2 + L_2^2} = n L₂
L₁² + L₂² = n² L₂²
L₁² = (n²-1) L₂²