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sveta [45]
3 years ago
12

Convert 1gcm-3 into kgm-3?

Physics
1 answer:
Rom4ik [11]3 years ago
3 0
When you have to convert a quantity you need to multiply by a fraction whose value is 1 but has different units of measurements.

In your case you have: \frac{1 g}{cm^{3} }

You will have two fractions: one that transforms grams into kilograms and one <span>that transforms</span> cm³ into m³. You need to position the quantities in such a way you can eliminate the original ones, therefore:

\frac{1 g}{1 cm^{3} }  \frac{10^{6} cm^{3} }{1 m^{3} }  \frac{1 kg}{10^{3} g}

Now, you can make the calculations and you get:

\frac{1g}{cm^{3} } = \frac{ 10^{3} kg }{m^{3} }

Therefore your answer is: 1000kg/m³



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The answer is A) First law of motion.
6 0
3 years ago
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A dragster in a race accelerated from stop to 60 m/s by the time it reached the finish line. The dragster moved in a straight li
Aleks [24]
Vf = final velocity
vo = initial velocity
a = acceleration
t = time

use the following equation

vf = vo + at

since vo = 0 m/s (stopped), that term drops out and you're left with . . .

vf = at

(60 m/s) = (8.0 m/s²)t

t = (60 m/s)/(8.0 m/s²) = 7.5 seconds

<u><em>t = 7.5 seconds</em></u>


7 0
4 years ago
A 25 Kg rock is sitting on a cliff that is 50 meters above the ground. If it fell off of the cliff, and all energy was conserved
svetlana [45]

Answer:

v = 31.32 [m/s]  

Explanation:

To solve this problem we must use the principle of energy conservation, which tells us that potential energy is converted into kinetic energy or vice versa. The potential energy can be calculated by the product of mass by gravity by height.

E_{pot}=m*g*h

where:

Epot = potential energy [J]

m = mass = 25 [kg]

g = gravity acceleration = 9.81 [m/s²]

h = elevation = 50 [m]

Now replacing:

E_{pot}=25*9.81*50\\E_{pot}= 12262.5[J]

When the rock falls the potential energy is converted into kinetic energy.

E_{pot}=E_{k}\\E_{k}=\frac{1}{2}*m*v^{2}

where:

Ek = kinetic energy [J]

v = velocity [m/s]

Now clearing v:

v^{2} =\frac{E_{k}*2}{m}\\v=\sqrt{(2*12262)/25}\\v = 31.32 [m/s]

8 0
3 years ago
A grandfather clock is controlled by a swinging brass pendulum that is 1.2 m long at a temperature of 27°C. (a) What is the leng
stealth61 [152]

Answer:

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

Explanation:

Given;

Initial length L1 = 1.2m

Initial temperature T1 = 27°C

Final temperature T2 = 0.0°C

Linear expansion coefficient of brass x = 1.9 × 10^-5 /°C

The change i length ∆L;

∆L = L2 - L1

L2 = L1 + ∆L ...........1

∆L = xL1(∆T)

∆L = xL1(T2 - T1) ......2

Substituting the given values into equation 2;

∆L = 1.9 × 10^-5 /°C × 1.2m × (0 - 27)

∆L = 1.9 × 10^-5 /°C × 1.2m × (- 27)

∆L = -6.156 × 10^-4 m

From equation 1;

L2 = L1 + ∆L

Substituting the values;

L2 = 1.2 m + (- 6.156 × 10^-4 m)

L2 = 1.2 m - 6.156 × 10^-4 m

L2 = 1.1993844 m

L2 = 1.1994 m

the length of the pendulum rod when the temperature drops to 0.0°C is 1.1994 m

3 0
3 years ago
What is the speed of light in carbon disulphide if its refractive index is 1.628?
Marina CMI [18]
Refractive index (symbol n) is defined as the ratio of the velocity of light in a vacuum (symbol c) to the velocity of light in a medium (symbol v). The equation is n=c/v. In order to obtain the speed of light in carbon disulphide the above equation needs to be rearranged to make v the subject. This yields v=c/n. Plugging the numbers in yields a speed to 1.84x10^8 metres per second. 
6 0
3 years ago
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