Answer:
d) Law of Conservation of Energy
Explanation:
The first law of thermodynamics states that energy can neither be created nor destroyed; energy can only change from one form to another.
For multiple choice you can use an elimination method. If you remember the law then you know it's not A or C because "energy cannot be created nor destroyed", and it's not B because it has nothing to do with mass.
Hope this helps!
The specific heat of the substance will be 0.129 J/g°C.
<h3>What is specific heat capacity?</h3>
The amount of heat required to increase a substance's temperature by one degree Celsius is known as specific heat capacity.
Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
The given data in the problem is;
Q is the amount of energy necessary to raise the temperature = 3,000.0 j
M is the mass= 0.465 kg.
Δt is the time it takes to raise the temperature.=50°c
s stands for specific heat capacity=?
Mathematically specific heat capacity is given by;

Hence the specific heat of the substance will be 0.129 J/g°C.
To learn more about the specific heat capacity refer to the link brainly.com/question/2530523
Answer:
4.5 N upward
Explanation:
You take the net force and subtract it from the weight
~DjMia~
Answer:
x=2.4t+4.9t^2
Explanation:
This equation is one of the kinematic equations to solve for distance. The original equation is as follows:
X=Xo+Vt+1/2at^2
We know that the ball starts at rest meaning that its initial velocity and position is zero.
X=0+Vt+1/2at^2
Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.
X=Vt+4.9t^2
Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.
Now, substitute in your velocity value.
X=2.4t+4.9t^2
Answer:
1.97 seconds
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 9.8 m/s²

Solving the above equation we get

So, the time the package was in the air is 1.97 seconds