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Marysya12 [62]
3 years ago
12

In a wind-turbine, the generator in the nacelle is rated at 690 V and 2.3 MW. It operates at a power factor of 0.85 (lagging) at

its rated conditions. Calculate the per-phase current that has to be carried by the cables to the power electronics converter and the step-up transformer located at the base of the tower.
Engineering
1 answer:
Juli2301 [7.4K]3 years ago
6 0

To solve this problem we will apply the concepts related to real power in 3 phases, which is defined as the product between the phase voltage, the phase current and the power factor (Specifically given by the cosine of the phase angle). First we will find the phase voltage from the given voltage and proceed to find the current by clearing it from the previously mentioned formula. Our values are

V = 690V

P_{real} = 2.3MW

Real power in 3 phase

P_{real} = 3V_{ph}I_{ph} Cos\theta

Now the Phase Voltage is,

V_{ph} = \frac{V}{\sqrt{3}}

V_{ph} = \frac{690}{\sqrt{3}}

V_{ph} = 398.37V

The current phase would be,

P_{real} = 3V_{ph}I_{ph} Cos\theta

Rearranging,

I_{ph}=\frac{P_{real}}{3V_{ph}Cos\theta}

Replacing,

I_{ph}=\frac{2.3MW}{3( 398.37V)(0.85)}

I_{ph}= 2.26kA/phase

Therefore the current per phase is 2.26kA

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