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Kryger [21]
3 years ago
14

Smith wants to get a job in network systems. Which major should he choose to give him the best chance of getting a job?

Engineering
2 answers:
frez [133]3 years ago
7 0
Computer engineering
Dafna11 [192]3 years ago
6 0
Computer engineering
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
enyata [817]

Answer:

Check image, right on PLATO

Explanation:

7 0
3 years ago
How do I find v0 using Kirchhoff's laws and Ohm's law? The answer is 25V but I'm confused about how to get that.
telo118 [61]

Answer:

  25 V

Explanation:

It is convenient to use Kirchoff's current law (KCL), which tells you the sum of currents into a node is zero. The node of interest is the top left node.

The currents into it are ...

  20 mA + (-5 -Vo)/(2kΩ) -(Vo/(5kΩ)) = 0

  20 mA -2.5 mA = Vo(1/(2kΩ) +1/(5kΩ)) . . . . add the opposite of Vo terms

  (17.5 mA)(10/7 kΩ) = Vo = 25 . . . volts . . . . divide by the coefficient of Vo

_____

You will notice that the equation resolves to what you would get if you drew the Norton equivalent of the voltage source with its 2k impedance. You have two current sources, one of +20 mA, and one of -2.5 mA supplying current to a load of 2k║5k = (10/7)kΩ. KCL tells you the total current into the node is equal to the current through that load (out of the node).

5 0
3 years ago
A boiler is designed to work at 14bar and evaporate 8 kg/s of water. The inlet water to the boiler has a temperature of 400C and
bearhunter [10]

Answer:

Explanation: 2 is thy answer

7 0
3 years ago
Air flows through a device such that the stagnation pressure is 0.4 MPa, the stagnation temperature is 400°C, and the velocity i
RoseWind [281]

To solve this problem it is necessary to apply the concepts related to temperature stagnation and adiabatic pressure in a system.

The stagnation temperature can be defined as

T_0 = T+\frac{V^2}{2c_p}

Where

T = Static temperature

V = Velocity of Fluid

c_p = Specific Heat

Re-arrange to find the static temperature we have that

T = T_0 - \frac{V^2}{2c_p}

T = 673.15-(\frac{528}{2*1.005})(\frac{1}{1000})

T = 672.88K

Now the pressure of helium by using the Adiabatic pressure temperature is

P = P_0 (\frac{T}{T_0})^{k/(k-1)}

Where,

P_0= Stagnation pressure of the fluid

k = Specific heat ratio

Replacing we have that

P = 0.4 (\frac{672.88}{673.15})^{1.4/(1.4-1)}

P = 0.399Mpa

Therefore the static temperature of air at given conditions is 72.88K and the static pressure is 0.399Mpa

<em>Note: I took the exactly temperature of 400 ° C the equivalent of 673.15K. The approach given in the 600K statement could be inaccurate.</em>

3 0
3 years ago
Question #4
inn [45]

Answer:

Deconstruction

Explanation:

8 0
3 years ago
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