Answer:
Answer to this question is option D i.e. unit price.
Explanation:
The unit price of the item can be understood as the price of a single product or one single commodity which forms a part of a group of items. When only one unit is to be sold then here comes the importance of 'unit price.' This is generally helpful in the retail sector where the products are bought in bulk after calculating the per-unit price of each commodity in that particular bulk.
Y = a (b)^t/p
y is total money
a is original amount
b is growth / decay factor
t is time
p is the frequency of every growth or decay
15131.76 = 11613 x 1.08^x
15131.76 / 11613 = 1.08^x
1.303… = 1.08^x
log1.303…. = xlog1.08
x = 3.43902165741 years
Answer:
k = 4.21 * 10⁻³(L/(mol.s))
Explanation:
We know that
k = Ae
------------------- euqation (1)
K= rate constant;
A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;
E = activation energy = 93.1kJ/mol;
R= ideal gas constant = 8.314 J/mol.K;
T= temperature = 332 K;
Put values in equation 1.
k = 4.36*10¹¹(M⁻¹s⁻¹)e![^{[(-93.1*10^3)(J/mol)]/[(8.314)(J/mol.K)(332K)}](https://tex.z-dn.net/?f=%5E%7B%5B%28-93.1%2A10%5E3%29%28J%2Fmol%29%5D%2F%5B%288.314%29%28J%2Fmol.K%29%28332K%29%7D)
k = 4.2154 * 10⁻³(M⁻¹s⁻¹)
here M =mol/L
k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)
or
k = 4.21 * 10⁻³((L/mol)s⁻¹)
or
k = 4.21 * 10⁻³(L/(mol.s))