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IRISSAK [1]
2 years ago
13

A TV USE 75 WATTS WHILE IN USED ASSMING THAT ITIS USED 4 HOURS EVERY DAY HOW MUCH ENERGY IN 4 IN KWH WOULD THE TV CONSUME ANNUAL

LY?.
Engineering
2 answers:
prohojiy [21]2 years ago
7 0

Answer:

i don't think i understand the question

Explanation:

alex41 [277]2 years ago
4 0

Answer:

Explanation:

The wattage listed is the maximum power drawn by the ... If John uses a window fan (200 watts) 4 hours a day for 120 ... TV, 120V, 75W.

                                                  or

75 w 4 hrs 30 days. So your total consumption is 75*4*30= 9000watt hr.

1 unit = 1000 watt hr.

9000 watt hr = 9 unit.

Total cost 9*2.5= RS 22.5

pls mark me as brainliest and this is a usefull answer pls dont delete

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Sunny_sXe [5.5K]

Answer:

Use linking words.

Explanation:

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The price of a single item within a group of items is
Nady [450]

Answer:

Answer to this question is option D i.e. unit price.

Explanation:

The unit price of the item can be understood as the price of a single product or one single commodity which forms a part of a group of items. When only one unit is to be sold then here comes the importance of 'unit price.' This is generally helpful in the retail sector where the products are bought in bulk after calculating the per-unit price of each commodity in that particular bulk.

7 0
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If you deposit today 11,613 in an account earning 8% compound interest, for how long should you invest the money in order to ear
Elanso [62]
Y = a (b)^t/p

y is total money

a is original amount

b is growth / decay factor

t is time

p is the frequency of every growth or decay

15131.76 = 11613 x 1.08^x

15131.76 / 11613 = 1.08^x

1.303… = 1.08^x

log1.303…. = xlog1.08

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3 0
2 years ago
Which explanation best summarizes what went wrong during Paul’s cost analysis?
Valentin [98]

Answer:

wut is it

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4 0
2 years ago
Using the results of the Arrhenius analysis (Ea=93.1kJ/molEa=93.1kJ/mol and A=4.36×1011M⋅s−1A=4.36×1011M⋅s−1), predict the rate
uysha [10]

Answer:

k = 4.21 * 10⁻³(L/(mol.s))

Explanation:

We know that

k = Ae^{-E/RT} ------------------- euqation (1)

K= rate constant;

A = frequency factor = 4.36 10^11 M⁻¹s⁻¹;

E = activation energy = 93.1kJ/mol;

R= ideal gas constant = 8.314 J/mol.K;

T= temperature = 332 K;

Put values in equation 1.

k = 4.36*10¹¹(M⁻¹s⁻¹)e^{[(-93.1*10^3)(J/mol)]/[(8.314)(J/mol.K)(332K)}

k = 4.2154 * 10⁻³(M⁻¹s⁻¹)

here M =mol/L

k = 4.21 * 10⁻³((mol/L)⁻¹s⁻¹)

 or

k = 4.21 * 10⁻³((L/mol)s⁻¹)

or

k = 4.21 * 10⁻³(L/(mol.s))

3 0
3 years ago
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