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IRISSAK [1]
2 years ago
13

A TV USE 75 WATTS WHILE IN USED ASSMING THAT ITIS USED 4 HOURS EVERY DAY HOW MUCH ENERGY IN 4 IN KWH WOULD THE TV CONSUME ANNUAL

LY?.
Engineering
2 answers:
prohojiy [21]2 years ago
7 0

Answer:

i don't think i understand the question

Explanation:

alex41 [277]2 years ago
4 0

Answer:

Explanation:

The wattage listed is the maximum power drawn by the ... If John uses a window fan (200 watts) 4 hours a day for 120 ... TV, 120V, 75W.

                                                  or

75 w 4 hrs 30 days. So your total consumption is 75*4*30= 9000watt hr.

1 unit = 1000 watt hr.

9000 watt hr = 9 unit.

Total cost 9*2.5= RS 22.5

pls mark me as brainliest and this is a usefull answer pls dont delete

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A train consists of a 50 Mg engine and three cars, each having a mass of 30 Mg . If it takes 75 s for the train to increase its
ohaa [14]

Answer:

T = 15 kN

F = 23.33 kN

Explanation:

Given the data in the question,

We apply the impulse momentum principle on the total system,

mv₁ + ∑\int\limits^{t2}_{t1} {Fx} \, dt = mv₂

we substitute

[50 + 3(30)]×10³ × 0 + FΔt = [50 + 3(30)]×10³ ×  ( 45 × 1000 / 3600 )  

F( 75 - 0 ) =  1.75 × 10⁶

The resultant frictional tractive force F is will then be;

F =  1.75 × 10⁶ / 75

F = 23333.33 N

F = 23.33 kN

Applying the impulse momentum principle on the three cars;

mv₁ + ∑\int\limits^{t2}_{t1} {Fx} \, dt = mv₂

[3(30)]×10³ × 0 + FΔt = [3(30)]×10³ ×  ( 45 × 1000 / 3600 )  

F(75-0) = 1.125 × 10⁶

The force T developed is then;

T =  1.125 × 10⁶ / 75

T = 15000 N

T = 15 kN

7 0
3 years ago
Technician A says that excessive end play causes rapid wear of the sealing rings and possibly the sealing ring groove. Technicia
DerKrebs [107]

Answer:

Technician A only

Explanation:

Rapid wear of the sealing ring and the seal ring groove are result of excessive end play

7 0
3 years ago
Heather is troubleshooting a computer at her worksite. She has interviewed the computer’s user and is currently trying to reprod
Luba_88 [7]

Answer:

The correct option is A

Explanation:

Heather is trying to establish a theory of probable cause. In this step of the troubleshooting process, the person troubleshooting questions the obvious and then test the theory or response given by the user to really determine the cause. Once confirmation of this theory has been achieved, the troubleshooter then tries to establish a resolution to the problem. However in the event whereby the theory is not confirmed, the troubleshooter then tries to establish a new theory.

8 0
3 years ago
Air at T1 = 32°C, p1 = 1 bar, 50% relative humidity enters an insulated chamber operating at steady state with a mass flow rate
RUDIKE [14]

Answer:

4.5kg/min

Explanation:

Given parameters

T_1 = 32^0 C,  m_1 = 3 kg/min, T_2 = 7^0 C ,T_3 = 17^0

if we take  

The mass flow rate of the second stream = m_2(kg/min)

The mass flow rate of mixed exit stream = m_3 (kg/min)

Now from mass conservation

m_3 = m_2 + m_1

m_3 = m_2 + 3 (kg/min)

The temperature of the mixed exit stream given as

T_3m_3 = T_2m_2 +T_1m_1\\\\17 ( 3 + m_2) = 7 \times m_2 + 32 \times 3\\\\51 + 17 m_2 = 7 m_2 + 96\\\\10 m_2 = 96 - 51\\\\m_2 = 4.5 kg/min\\\\\\\\

Therefore the mass flow rate of second stream will be 4.5 kg/min.

7 0
3 years ago
zener shunt regulator employs a 9.1-V zener diode for which VZ = 9.1 V at IZ = 9 mA, with rz = 40 and IZK= 0.5 mA. The available
gulaghasi [49]

Answer:

V_z=9.1v

V_{zo}=8.74V

I=10mA

R=589 ohms

Explanation:

From the question we are told that:

Zener diode Voltage V_z=9.1-V

Zener diode Current I_z=9 .A

Note

rz = 40\\\\IZK= 0.5 mA

Supply Voltage V_s=15

Reduction Percentage P_r= 50 \%

Generally the equation for Kirchhoff's Voltage Law is mathematically given by

V_z=V_{zo}+I_zr_z

9.1=V_{z0}+9*10^{-3}(40)

V_{zo}=8.74V

Therefore

At I_z-10mA

V_z=V_{z0}+I_zr_z

V_z=8.74+(10*10^{-3}) (40)

V_z=9.1v

Generally the equation for Kirchhoff's Current Law is mathematically given by

-I+I_z+I_l=0

I=10mA+\frac{V_z}{R_l}

I=10mA+\frac{9.1}{0}

I=10mA

Therefore

R=\frac{15V-V_z}{I}

R=\frac{15-9.1}{10*10^{-3}}

R=589 ohms

5 0
3 years ago
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