Question

Consider the following Moore’s law growth pattern (since 1980) for the number of transistors inside a particular commercial microprocessor: N = 1920 x 10 0.1637(Y – 1980) where Y is the year and N is the number of transistors. Assuming sustained Moore’s law growth, what will be the number of transistors in a microprocessor in year 2025? Using the same expression, calculate how many years it will take for the transistor count to increase by 100x

Answer 1

Answer:

No. of transistors = $4.1524 \times 10^{10}$ transistors

Explanation:

Given that:

N = $1920 \times 10^{0.163(Y-1980)}$

Y = 2025

N = $1920 \times 10^{0.163(2025-1980)}$

N = $4.1524 \times 10^{10}$ transistors

Now at Y = 1980

Number of transistors N = 1920

Therefore,

$1000 = 10^{0.163(Y-1980)}$

$\log_{10} 1000=0.163(Y-1980)$

$\frac{3}{0.163}=Y-1980$

18 ≅ 18.4 = Y - 1980

Y = 1980 + 18

   = 1998

So, to increase multiples of 1000 transistors. it takes 18 years.