Answer:
0Nm, no work is done.
Explanation:
Work done is defined as the Force per distance meaning force times the distance moved in the direction of the force.
Now the body of mass 50g has a centripetal force acting on it directed towards the centre. Now in actuality the body stays along the circle it doesn't really move to the centre of the circle.
Hence the force doesn't move a distance, and so from the definition of work done;
F×d ; d =0
Hence work done = mv2/r × 0= 0Nm
Let Regent Lead The Way
No matter your passion, you'll find your place at Regent! Choose from more than 95 areas of study in the subject areas employers deman
Answer:
The question is missing something it doesn't say how fast down its going and doesn't show the figure sorry for wasting an answer
Answer:
<em>No, a rigid body cannot experience any acceleration when the resultant force acting on the body is zero.</em>
Explanation:
If the net force on a body is zero, then it means that all the forces acting on the body are balanced and cancel out one another. This sate of equilibrium can be static equilibrium (like that of a rigid body), or dynamic equilibrium (that of a car moving with constant velocity)
For a body under this type of equilibrium,
ΣF = 0 ...1
where ΣF is the resultant force (total effective force due to all the forces acting on the body)
For a body to accelerate, there must be a force acting on it. The acceleration of a body is proportional to the force applied, for a constant mass of the body. The relationship between the net force and mass is given as
ΣF = ma ...2
where m is the mass of the body
a is the acceleration of the body
Substituting equation 2 into equation 1, we have
0 = ma
therefore,
a = 0
this means that<em> if the resultant force acting on a rigid body is zero, then there won't be any force available to produce acceleration on the body.</em>
<em></em>
The big bang theory is the most accepted theory regarding the origin of the solar system. It suggests that our star, the Sun, was first created by a cloud of<span>dust and gas.</span>
