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3 years ago

8

A ball is thrown straight up from the ground with an unknown velocity. It reaches its highest point after 5.5 s. With what veloc

ity did it leave the ground?

1 answer:

Maslowich3 years ago

5 0

V = u + at
0 = u -9.8 x 5.5
u = 9.8 x 5.5 = 53.9 m/s

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$e=3367.2J$

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Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

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Since the speedometer is only accurate to within 0.1km/h the experimental speed is

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Knowing that we can calculate Kinetic energy for the real and experimental speed

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Now, the potential error in her calculated kinetic energy is:

$e=E_{r}-E_{e}=(234023-230656)J=3367.2J$

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Answer:

#See solution for details.

Explanation:

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