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GrogVix [38]
4 years ago
8

A ball is thrown straight up from the ground with an unknown velocity. It reaches its highest point after 5.5 s. With what veloc

ity did it leave the ground?
Physics
1 answer:
Maslowich4 years ago
5 0
V = u + at
0 = u -9.8 x 5.5
u = 9.8 x 5.5 = 53.9 m/s
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El peso de un cuerpo es de 392.2 N ¿Cuál es su masa?
alexandr1967 [171]

Answer:

⇒ To find the mass, we apply the following formula:

                         \boxed{ \boxed{\mathbf{m=\dfrac{w}{g} }}}

<u>Data</u>:

➢  \textrm{Weight(w) = 392.2 Newtons}

➢  \mathrm{Gravity(g) = \ 9,81\ m/s^{2} }

➢  \textrm{Mass(m) =\ ?}

∴ We replace and develop:

\mathrm{m=\dfrac{w}{g} }

\mathrm{Mass=\dfrac{392.2}{9.81} }

\mathrm{Mass =39.9\ kg }

<h2>Body mass is 39.9 kg</h2>
3 0
3 years ago
The weight of a 72.0 kg astronaut on the Moon, where g = 1.63 m/s2 is (5 points) Select one: a. 112 N b. 117 N c. 135 N d. 156 N
Hunter-Best [27]

Answer: The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

Explanation:

Mass of the astronaut on the moon , m= 72 kg

Acceleration due to gravity on moon,g  = 1.63 m/s^2

According to Newton second law of motion: F = ma

This will changes to = Weight = mass × g

Weight=72 kg\times 1.63m/s^2=117.36 N

The weight of a 72.0 kg astronaut on the Moon is 117.36 N.

5 0
4 years ago
Read 2 more answers
Three samples of gas each exert 740. mm Hg in separate 2 L containers. What pressure do they exert if they are all placed in a s
Usimov [2.4K]
According to Dalton's law of partial pressure, the total pressure exerted is simply equal to the sum of the partial pressures of the individual gases. Given that all three samples of gas each exert 740 mmHg, when they are placed in a single 2 L container, they exert a pressure of 2220 mmHg on the container which is the sum of their individual pressures. 
5 0
4 years ago
Design a tension member and slip-critical splice to carry a factored load of 500 kips. Please use a wide-flange section for the
Svetlanka [38]

Answer:

Kindly check the explanation section.

Explanation:

For the design we are asked for in this question/problem there is the need for us to calculate or determine the strength in fracture and that of the yield. Also, we need to calculate for the block shear strength.

From the question, we have that the factored load = 500kips. Also, note that the tension splice must not slip.

Also, the shear force are resisted by friction, that is to say shear resistance = 1.13 × Tb × Ns.

Assuming our db = 3/4 inches, then the slip critical resistance to shear service load = 18ksi(refer to AISC manual for the table).

If db = 7/8 inches, then the shear force resistance for n bolt = 10.2kips, n > 49.6.

The yielding strength = 0.9 × Aj × Fhb= 736 kips > 500

The fracture strength = .75 × Ah × Fhb = 309 kips.

The bearing strength of 7/8 inches bolt at the edge hole and other holes = 46 kips and 102 kips.

4 0
4 years ago
GIVING EASY BRAINLIEST PLEASE HELP!!
Kryger [21]

Answer:

Y

Explanation:

The fulcrum is the point where the scissor blades are joined together. The force or effort is the end or handle of the scissors. The parts of a pair of pliers are similar to the scissors.

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