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GrogVix [38]
3 years ago
8

A ball is thrown straight up from the ground with an unknown velocity. It reaches its highest point after 5.5 s. With what veloc

ity did it leave the ground?
Physics
1 answer:
Maslowich3 years ago
5 0
V = u + at
0 = u -9.8 x 5.5
u = 9.8 x 5.5 = 53.9 m/s
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Find the electric field at a point midway between two charges of 30.0×10 power -9 and 60.0×10 power -9 separated by a distance o
KATRIN_1 [288]

Answer:

The electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C

Explanation:

Let the midpoint of the two charges be considered as the origin, and charge A = 30.0 * 10⁻⁹ C be moving in the +x- axis and the charge B = 60.0 * 10⁻⁹ C be moving in the -x-axis.

Electric field, E = kQ/r² where k is a constant = 9.0 * 10⁹  N.m²/C², Q = quantity of charge, r = distance of separation

In the given question,r = 30.0 cm = 0.03 m; the midway point between A and B = 0.03/2 = 0.015 m

Electric field due to charge A

Ea = +(9.0 * 10⁹  N.m²/C² * 30.0 * 10⁻⁹ ) / ( 0.015 m)²

Ea =  +1.8 * 10⁴ N/C

Electric field due to charge B

Eb = -(9.0 * 10⁹  N.m²/C² * 60.0 * 10⁻⁹ ) / ( 0.015 m)²

Eb =  -3.6 * 10⁴ N/C

The resultant electric field E = Ea + Eb

E = (+1.8 * 10⁴  +  -3.6 * 10⁴) N/C

E = -1.8 * 10⁴ N/C

Therefore, the electric field at a point midway between the two charges, E = -1.8 * 10⁴ N/C

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Find the correct statement
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Answer:

The smallest radius will be four (4) times the initial radius

Explanation:

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Replacing 2 in 1

3. F_{r}=m*\frac{v^2}{R_{p}}

Where:

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Rp= Initial Radius

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Also we have that:

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Replacing 4 in 5

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Simplifying

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Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7

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Computing

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Replacing 5 in 9

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Explanation:

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